What mass of anhydrous Sodium trioxocarbonate(vi) present in 750cm of 0.1mol/dm
To find the mass of anhydrous Sodium trioxocarbonate(vi) present in 750 cm³ of a 0.1 mol/dm³ solution, we can use the formula:
Mass = Volume x Concentration x Molar mass
First, we need to convert the volume from cm³ to dm³. Since 1 dm³ = 1000 cm³, 750 cm³ is equal to 0.75 dm³.
Next, we need to calculate the number of moles of Sodium trioxocarbonate(vi) using the concentration and volume. The formula for moles is:
Moles = Concentration x Volume
Moles = 0.1 mol/dm³ x 0.75 dm³ = 0.075 mol
Finally, we can calculate the mass using the molar mass of Sodium trioxocarbonate(vi), which is 105.99 g/mol.
Mass = Moles x Molar mass
Mass = 0.075 mol x 105.99 g/mol
Mass = 7.94925 g
Therefore, the mass of anhydrous Sodium trioxocarbonate(vi) present in 750 cm³ of a 0.1 mol/dm³ solution is approximately 7.95 grams.
To calculate the mass of anhydrous Sodium trioxocarbonate (vi) in 750 cm^3 of 0.1 mol/dm^3 solution, we need to use the formula:
Mass = Volume x Concentration x Molar Mass
1. First, convert the volume from cm^3 to dm^3:
Volume = 750 cm^3 = 750/1000 dm^3 = 0.75 dm^3
2. The concentration is given as 0.1 mol/dm^3.
3. The molar mass of Sodium trioxocarbonate (vi) is calculated as follows:
- Sodium (Na) has an atomic mass of 22.99 g/mol.
- Carbon (C) has an atomic mass of 12.01 g/mol.
- Oxygen (O) has an atomic mass of 16.00 g/mol.
The molecular formula of Sodium trioxocarbonate (vi) is Na2CO3.
So, the molar mass of Na2CO3 = (2 x 22.99) + 12.01 + (3 x 16.00)
4. Calculate the mass:
Mass = 0.75 dm^3 x 0.1 mol/dm^3 x (2 x 22.99 + 12.01 + 3 x 16.00) g/mol
By substituting the values, we can calculate the answer.
To find the mass of anhydrous Sodium trioxocarbonate(VI) (Na2CO3) present in 750 cm³ of a 0.1 mol/dm³ solution, we can use the formula:
Mass = Molar concentration x Volume x Molar mass
1. Calculate the number of moles of Na2CO3:
Moles = Molar concentration x Volume
Moles = 0.1 mol/dm³ x (750 cm³ / 1000)
Moles = 0.1 x 0.75
Moles = 0.075 mol
2. Find the molar mass of Na2CO3:
The molar mass of Na2CO3 can be found by adding up the atomic masses of its elements.
Na (Sodium) atomic mass = 23 g/mol
C (Carbon) atomic mass = 12 g/mol
O (Oxygen) atomic mass = 16 g/mol
Molar mass of Na2CO3 = (2 x Na atomic mass) + C atomic mass + (3 x O atomic mass)
Molar mass of Na2CO3 = (2 x 23) + 12 + (3 x 16)
Molar mass of Na2CO3 = 46 + 12 + 48
Molar mass of Na2CO3 = 106 g/mol
3. Calculate the mass of Na2CO3:
Mass = Moles x Molar mass
Mass = 0.075 mol x 106 g/mol
Mass = 7.95 g
Therefore, the mass of anhydrous Sodium trioxocarbonate(VI) present in 750 cm³ of a 0.1 mol/dm³ solution is approximately 7.95 grams.