calculate the mass of zinc that will produce 35.8g of zinc trioxonitrate(V) 3Zn +8HNO3➡️ 3Zn(NO3)2 +4H2O + 2NO
To calculate the mass of zinc that will produce 35.8g of zinc trioxonitrate(V) (Zn(NO3)2), we need to determine the molar ratio between zinc and zinc trioxonitrate(V) in the balanced equation.
From the balanced equation:
3 moles of zinc (Zn) produce 1 mole of zinc trioxonitrate(V) (Zn(NO3)2)
We know the molar mass of Zn(NO3)2:
Molar mass of Zn(NO3)2 = (1 x atomic mass of Zn) + (2 x atomic mass of N) + (6 x atomic mass of O)
= (1 x 65.38 g/mol) + (2 x 14.01 g/mol) + (6 x 16.00 g/mol)
= 65.38 g/mol + 28.02 g/mol + 96.00 g/mol
= 189.40 g/mol
Now, we can calculate the moles of Zn(NO3)2:
moles of Zn(NO3)2 = mass of Zn(NO3)2 / molar mass of Zn(NO3)2
= 35.8 g / 189.40 g/mol
≈ 0.1892 mol
Since the molar ratio between zinc (Zn) and zinc trioxonitrate(V) (Zn(NO3)2) is 3:1, we can determine the moles of zinc:
moles of Zn = moles of Zn(NO3)2 x 3
= 0.1892 mol x 3
≈ 0.5676 mol
Finally, we can calculate the mass of zinc:
mass of Zn = moles of Zn x molar mass of Zn
= 0.5676 mol x 65.38 g/mol
≈ 37.1 g
Therefore, the mass of zinc that will produce 35.8g of zinc trioxonitrate(V) is approximately 37.1 grams.
To calculate the mass of zinc required to produce 35.8g of zinc trioxonitrate(V) (Zn(NO3)2), you need to use stoichiometry.
The balanced equation shows that 3 moles of zinc react with 3 moles of zinc trioxonitrate(V). This means that the molar ratio of zinc to zinc trioxonitrate(V) is 3:3 or 1:1.
1 mole of zinc has a molar mass of approximately 65.38g (according to the periodic table), so we can use this information to calculate the mass of zinc required.
First, we need to calculate the number of moles of zinc trioxonitrate(V) produced:
Mass of zinc trioxonitrate(V) = 35.8g
Molar mass of zinc trioxonitrate(V) = 2 * (65.38g + 3 * (14.01g + 16.00g) + 3 * (14.01g + 16.00g))
= 189.398g/mol
Number of moles of zinc trioxonitrate(V) = Mass / Molar mass
= 35.8g / 189.398g/mol
≈ 0.189 mol
Since the molar ratio between zinc and zinc trioxonitrate(V) is 1:1, we know that the number of moles of zinc required is also 0.189 mol.
Now, we can calculate the mass of zinc:
Mass of zinc = Number of moles × Molar mass
= 0.189 mol × 65.38g/mol
≈ 12.36g
Therefore, approximately 12.36g of zinc is required to produce 35.8g of zinc trioxonitrate(V) according to the balanced equation.
To calculate the mass of zinc required to produce 35.8g of zinc trioxonitrate(V) (Zn(NO3)2), you need to determine the molar ratios and the molar masses of the substances involved.
Step 1: Write down the balanced chemical equation:
3Zn + 8HNO3 → 3Zn(NO3)2 + 4H2O + 2NO
According to the balanced equation, 3 moles of zinc (Zn) reacts with 8 moles of nitric acid (HNO3) to form 3 moles of zinc trioxonitrate(V) (Zn(NO3)2).
Step 2: Determine the molar masses:
- Molar mass of Zn = 65.38 g/mol
- Molar mass of Zn(NO3)2 = 189.36 g/mol
Step 3: Convert the given mass of Zn(NO3)2 to moles:
moles = mass / molar mass
moles of Zn(NO3)2 = 35.8 g / 189.36 g/mol
Step 4: Use the molar ratio to find the moles of Zn:
From the balanced equation, the molar ratio between Zn(NO3)2 and Zn is 1:3.
moles of Zn = moles of Zn(NO3)2 × (3 moles of Zn / 1 mole of Zn(NO3)2)
Step 5: Calculate the mass of Zn:
mass = moles × molar mass
mass of Zn = moles of Zn × molar mass of Zn
Now, let's calculate the mass of zinc:
1. Calculate moles of Zn(NO3)2:
moles of Zn(NO3)2 = 35.8 g / 189.36 g/mol ≈ 0.1896 mol
2. Use the molar ratio to find moles of Zn:
moles of Zn = 0.1896 mol × (3 mol Zn / 1 mol Zn(NO3)2) ≈ 0.5688 mol
3. Calculate the mass of Zn:
mass of Zn = 0.5688 mol × 65.38 g/mol ≈ 37.19 g
Therefore, approximately 37.19 grams of zinc is needed to produce 35.8 grams of zinc trioxonitrate(V).