If EF ≅ FG, EH = 2s, and GH = s + 28, what is the value of s?
If EF ≅ FG, then EF = FG. And if EH = 2s and GH = s + 28, we know that FH = EH + GH = 2s + (s + 28) = 3s + 28.
Since EF = FG, we can conclude that EFH and FGH form a straight line. So EFH + FGH = 180°.
From EFH, we have:
180° = 90° + (3s + 28)
90° = 3s + 28
62° = 3s
s = 62°/3
s ≈ <<20.666666666666668=20.67>>20.67. Answer: \boxed{20.67}.
We can solve for the value of s using the given information.
Given:
EF ≅ FG
EH = 2s
GH = s + 28
Since EF ≅ FG, we can conclude that EH = GH.
So, we have:
2s = s + 28
To solve this equation, we can subtract s from both sides:
2s - s = s + 28 - s
This simplifies to:
s = 28
Therefore, the value of s is 28.
To find the value of s, we can use the given information and solve for it step by step.
First, we know that EF ≅ FG, which means that the lengths of EF and FG are equal. This implies that EH + HG = EF + FG. Substituting the values we have, EH + HG = 2s + (s + 28), or EH + HG = 3s + 28.
Since EH is given as 2s and HG is given as s + 28, we can substitute these values into the equation: 2s + (s + 28) = 3s + 28.
Now, let's simplify the equation: 2s + s + 28 = 3s + 28.
Combining like terms, we get: 3s + 28 = 3s + 28.
Subtracting 3s from both sides, we have: 28 = 28.
This equation is true for any value of s, meaning that s can have any value.
Therefore, the value of s is indeterminate.