Evaluate 6a+4b~3c when a=4,b=7and c=‘2
To evaluate the expression 6a + 4b - 3c when a=4, b=7, and c=2, we substitute these values into the expression:
6a + 4b - 3c = 6(4) + 4(7) - 3(2)
Now, performing the multiplication and subtraction:
= 24 + 28 - 6
Finally, we perform the addition:
= 52 - 6
= 46
Therefore, when a=4, b=7, and c=2, 6a + 4b - 3c equals 46.
To evaluate the expression 6a + 4b - 3c when a=4, b=7, and c=2, follow these steps:
Step 1: Substitute the given values of a, b, and c into the expression.
6(4) + 4(7) - 3(2)
Step 2: Simplify the multiplication within the expression.
24 + 28 - 6
Step 3: Calculate the additions and subtractions.
52 - 6
Step 4: Perform the subtraction to get the final answer.
46
Therefore, when a=4, b=7, and c=2, the expression 6a + 4b - 3c evaluates to 46.
To evaluate the expression 6a + 4b - 3c when a = 4, b = 7, and c = 2, you can substitute the values of a, b, and c into the expression and perform the arithmetic.
Given:
a = 4
b = 7
c = 2
Substituting these values into the expression:
6a + 4b - 3c = 6(4) + 4(7) - 3(2)
Now, let's simplify the expression using the order of operations (PEMDAS/BODMAS):
6(4) + 4(7) - 3(2) = 24 + 28 - 6
Now, perform the operations from left to right:
24 + 28 - 6 = 52 - 6
Lastly, subtract:
52 - 6 = 46
Therefore, when a = 4, b = 7, and c = 2, evaluating the expression 6a + 4b - 3c results in 46.