If 450. mL of 6.0 M KBr solution is diluted to 900. mL, the concentration of the KBr solution is _ _M.
To find out the concentration of the KBr solution after dilution, we can use the following formula:
(Initial volume) x (Initial concentration) = (final volume) x (final concentration)
(450 mL) x (6.0 M) = (900 mL) x (final concentration)
Let's solve for the final concentration:
(450 mL) x (6.0 M) = (900 mL) x (final concentration)
2700 M mL = 900 mL x (final concentration)
Now we can divide both sides of the equation by 900 mL:
2700 M mL / 900 mL = final concentration
3.0 M = final concentration
Therefore, the concentration of the KBr solution after dilution is 3.0 M.
To find the concentration of the KBr solution after dilution, we can use the formula:
C1V1 = C2V2
Where:
C1 = initial concentration
V1 = initial volume
C2 = final concentration
V2 = final volume
Given:
Initial concentration (C1) = 6.0 M
Initial volume (V1) = 450 mL
Final volume (V2) = 900 mL
Let's substitute the values into the formula and solve for the final concentration (C2):
C1V1 = C2V2
(6.0 M)(450 mL) = C2(900 mL)
To find C2, divide both sides of the equation by 900 mL:
(6.0 M)(450 mL) / 900 mL = C2
C2 ≈ 3.0 M
Therefore, the concentration of the KBr solution after dilution is approximately 3.0 M.
To find the concentration of the KBr solution after dilution, you can use the formula:
(C1)(V1) = (C2)(V2)
where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
In this case, we are given:
C1 = 6.0 M (initial concentration of KBr solution)
V1 = 450 mL (initial volume of KBr solution)
C2 = ? (final concentration of KBr solution after dilution)
V2 = 900 mL (final volume of KBr solution after dilution)
We want to solve for C2, so we can rearrange the formula to solve for C2:
C2 = (C1)(V1) / V2
Plugging in the given values, we have:
C2 = (6.0 M)(450 mL) / 900 mL
Now, let's calculate the final concentration:
C2 = 2700 mL•M / 900 mL
C2 = 3.0 M
Therefore, the concentration of the KBr solution after dilution is 3.0 M.