4.50 moles of glucose in 4.00 L of a glucose solution
Express your answer with the appropriate units.
To find the concentration of glucose in the solution, we need to divide the number of moles by the volume of the solution.
Concentration = Moles / Volume
Concentration = 4.50 moles / 4.00 L
Concentration = 1.125 mol/L
Therefore, the concentration of glucose in the solution is 1.125 mol/L.
To express the concentration of 4.50 moles of glucose in a 4.00 L glucose solution, we need to use the unit of molarity (M).
Molarity is defined as the number of moles of solute per liter of solution.
Therefore, the concentration of the glucose solution can be calculated as follows:
Concentration = moles of solute / volume of solution
Concentration = 4.50 moles / 4.00 L
Concentration = 1.125 M
Therefore, the concentration of the glucose solution is 1.125 M.
To find the concentration of the glucose solution, we need to divide the number of moles of glucose by the volume of the solution.
Given:
Moles of glucose = 4.50 mol
Volume of solution = 4.00 L
Concentration is defined as moles per liter, so the formula for concentration is:
Concentration (in mol/L) = Moles of solute / Volume of solution
Now, let's calculate the concentration:
Concentration = 4.50 mol / 4.00 L
Concentration = 1.125 mol/L
Therefore, the concentration of the glucose solution is 1.125 mol/L.