What is a counterexample for the conjecture?
Conjecture: Any number that is divisible by 3 is also divisible by 6.
(1 point)
9
12
26
30
The counterexample for this conjecture is 9. 9 is divisible by 3 but not divisible by 6.
To find a counterexample for the conjecture, we need to find a number that is divisible by 3 but not by 6.
Out of the given numbers, 9 is divisible by 3, but it is not divisible by 6. Therefore, 9 is the counterexample for this conjecture.
To find a counterexample for the conjecture, we need to find a number that is divisible by 3 but not divisible by 6.
Let's look at the given options:
- 9: 9 is divisible by 3, but it is also divisible by 6 since 6 is a multiple of 3.
- 12: 12 is divisible by both 3 and 6, so it does not serve as a counterexample.
- 26: 26 is not divisible by 3, so it cannot be a counterexample.
- 30: 30 is divisible by both 3 and 6, so it does not serve as a counterexample either.
Therefore, none of the given options provide a counterexample to the conjecture.