The temperature at the end of the day was 64 degrees. The temperature had increased twice during the day, once by 8 degrees and another time by 4 degrees. Which expression shows what the temperature was at the start of the day? (1 point)
Let x be the temperature at the start of the day.
After the first increase, the temperature is x + 8 degrees.
After the second increase, the temperature is (x + 8) + 4 = x + 12 degrees.
The temperature at the end of the day is x + 12 = 64 degrees.
Subtracting 12 from both sides, we get x = 52 degrees.
So, the expression that shows the temperature at the start of the day is x = 52 degrees. Answer: \boxed{52}.
To find the temperature at the start of the day, we need to subtract the total increase in temperature from the end of the day temperature.
The temperature first increased by 8 degrees, and then increased again by 4 degrees.
So the total increase in temperature is 8 + 4 = 12 degrees.
To find the temperature at the start of the day, we subtract the total increase from the end of the day temperature:
64 degrees - 12 degrees = 52 degrees.
Therefore, the expression that shows what the temperature was at the start of the day is 52 degrees.
To find the temperature at the start of the day, we need to subtract the increases in temperature from the final temperature at the end of the day.
Given that the temperature increased by 8 degrees and then by 4 degrees, the total increase in temperature is 8 + 4 = 12 degrees.
To find the temperature at the start of the day, we subtract the total increase from the final temperature:
Start temperature = Final temperature - Total increase
Start temperature = 64 degrees - 12 degrees
Therefore, the expression that shows what the temperature was at the start of the day is:
64 - 12 = 52 degrees