Solve this multi-step problem. A runner completes 1/4 of a 5-mile race every 8 minutes. At the same pace, how far can the runner go in 16 minutes?(1 point) Responses 110 mile Start Fraction 1 over 10

If the runner completes 1/4 of a 5-mile race every 8 minutes, that means the runner completes 1 mile every 2 minutes (since 1/4 of 5 is 1.25 and 8 divided by 4 is 2).

Therefore, in 16 minutes, the runner can complete 8 miles (since 16 divided by 2 is 8).

So, the runner can go 8 miles in 16 minutes.

To solve this problem, we'll first find out how far the runner can go in 8 minutes and then double that distance to find out how far the runner can go in 16 minutes.

Given that the runner completes 1/4 of a 5-mile race every 8 minutes, we can find the distance covered in 8 minutes by multiplying 1/4 by 5 miles:

(1/4) * 5 miles = 5/4 miles

So, the runner can cover 5/4 miles in 8 minutes.

To find out the distance covered in 16 minutes, we can double this distance:

(5/4 miles) * 2 = 10/4 miles = 2.5 miles

Therefore, the runner can go 2.5 miles in 16 minutes.

To solve this multi-step problem, we need to find the distance the runner can cover in 16 minutes at the same pace as completing 1/4 of a 5-mile race every 8 minutes.

First, let's calculate how many sets of 8 minutes are there in 16 minutes. We divide 16 minutes by 8 minutes:

16 minutes ÷ 8 minutes = 2 sets

So, in 16 minutes, there are 2 sets of 8 minutes.

Next, we need to determine how much distance the runner covers in 8 minutes. We know that the runner completes 1/4 of a 5-mile race every 8 minutes. To find out how much distance that is, we multiply 1/4 by 5 miles:

1/4 × 5 miles = 1.25 miles

Therefore, the runner covers 1.25 miles in 8 minutes.

Now, we can find out how far the runner can go in 16 minutes by multiplying the distance covered in 8 minutes by the number of sets of 8 minutes (which is 2):

1.25 miles × 2 sets = 2.5 miles

Hence, at the same pace, the runner can go 2.5 miles in 16 minutes.

So, the correct answer is 2.5 miles, not 110 miles.