Find the value of x to make this exponential equation true... 5^×÷5^5=5^12
To solve the equation 5^x ÷ 5^5 = 5^12, we can use the property of exponents that states: a^m ÷ a^n = a^(m-n).
Applying this property, we have:
5^x ÷ 5^5 = 5^12
By subtracting the exponents, we can rewrite the equation as:
5^(x-5) = 5^12
For the equation to be true, the exponent on both sides must be equal. Therefore, we have:
x - 5 = 12
Adding 5 to both sides, we find:
x = 17
Therefore, the value of x to make the exponential equation true is 17.
To find the value of x that makes the exponential equation true, we can equate the exponents on both sides of the equation.
The equation is:
5^x ÷ 5^5 = 5^12
We know that when dividing with the same base, we subtract the exponents. So, let's subtract the exponent of 5^5 from the exponent of 5^x.
x - 5 = 12
To solve for x, we can add 5 to both sides of the equation.
x = 12 + 5
Therefore, the value of x that makes the exponential equation true is x = 17.
To find the value of x that makes the equation 5^x ÷ 5^5 = 5^12 true, we can use the properties of exponents.
First, let's rewrite the equation using the property of division of exponents:
5^x ÷ 5^5 = 5^12
Now, let's apply the property of division, which states that when dividing two exponents with the same base, we subtract the exponents:
5^(x-5) = 5^12
Since the bases are the same (both are 5), the exponents must be equal:
x - 5 = 12
To solve for x, we can add 5 to both sides of the equation:
x = 12 + 5
x = 17
Therefore, the value of x that makes the exponential equation true is 17.