A scientist isolated DNA from a particular bacterium and decided to analyze it. The sequence of the bacterial DNA is ATGGGCTAGTCTT. What will the complementary strand be?
A.
TACCCGATCAGTTA
B.
TACCCGATCAGAA
C.
TACCCGAGGCGAA
D.
TACAAGATCAGAA
The complementary strand of DNA is formed by pairing each nucleotide with its complementary base. In DNA, adenine pairs with thymine, and guanine pairs with cytosine.
The given bacterial DNA sequence is ATGGGCTAGTCTT. To find the complementary strand, we need to determine the base pairing for each nucleotide.
A --> T
T --> A
G --> C
C --> G
Therefore, the complementary strand of the given bacterial DNA sequence is TACCCGATCAGAA.
The correct answer is option D.
The complementary strand of DNA can be determined by pairing each nucleotide with its complementary base. In DNA, adenine (A) pairs with thymine (T), and guanine (G) pairs with cytosine (C).
Given the sequence of the bacterial DNA as ATGGGCTAGTCTT, the complementary strand will be:
ATGGGCTAGTCTT
TACCCGATCAGAA
Therefore, the correct answer is B. TACCCGATCAGAA.
To determine the complementary strand of DNA, you need to understand the pairing rule of DNA bases. In DNA, adenine (A) pairs with thymine (T), and cytosine (C) pairs with guanine (G).
Given the sequence of the bacterial DNA as ATGGGCTAGTCTT, you can find the complementary strand by replacing each base with its pairing base. Here's how:
A (adenine) pairs with T (thymine).
T (thymine) pairs with A (adenine).
G (guanine) pairs with C (cytosine).
C (cytosine) pairs with G (guanine).
Now, let's apply these rules to the given sequence ATGGGCTAGTCTT:
A (adenine) → T (thymine)
T (thymine) → A (adenine)
G (guanine) → C (cytosine)
G (guanine) → C (cytosine)
C (cytosine) → G (guanine)
T (thymine) → A (adenine)
A (adenine) → T (thymine)
G (guanine) → C (cytosine)
T (thymine) → A (adenine)
C (cytosine) → G (guanine)
T (thymine) → A (adenine)
Therefore, the complementary strand of the given DNA sequence ATGGGCTAGTCTT is TACCCGATCAGAA. So, option D, TACAAGATCAGAA, is the correct answer.