An airplane 28,000 feet above ground begins descending at a constant rate of 2,000 feet per minute. Which equation gives the height, h, of the airplane after m minutes?
Question 6 options:
h = 28,000m + 2,000
h = 2,000m + 28,000
h = 2,000 − 28,000m
h = 28,000 − 2,000m
h = 28,000 - 2,000m
To find the equation that gives the height, h, of the airplane after m minutes, we can start by recognizing that the airplane is descending at a constant rate of 2,000 feet per minute.
This means that for every minute that passes, the airplane's height decreases by 2,000 feet.
Therefore, the initial height of the airplane (when m = 0) is 28,000 feet.
To find the height after m minutes, we can subtract 2,000 feet for each minute that has passed.
So the equation that gives the height, h, of the airplane after m minutes is:
h = 28,000 - 2,000m
Therefore, the correct answer is:
h = 28,000 - 2,000m
To solve this problem, we need to understand that the height of the airplane is decreasing at a constant rate of 2,000 feet per minute. This means that for every minute that passes, the height decreases by 2,000 feet.
Let's consider the starting height of the airplane, which is 28,000 feet. After 1 minute, the height will decrease by 2,000 feet, so it will be 28,000 - 2,000 = 26,000 feet. After 2 minutes, it will be 26,000 - 2,000 = 24,000 feet. And so on.
From this pattern, we can see that for every minute (m) that passes, the height (h) decreases by 2,000 feet. This means we need to subtract 2,000m from the starting height of 28,000 feet.
Therefore, the correct equation for the height, h, of the airplane after m minutes is:
h = 28,000 - 2,000m
So, the answer is h = 28,000 - 2,000m.