Identify the vertex and the axis of symmetry of the graph of the function y = 3(x + 2)2 – 3. (1 point) Responses vertex: (2, –3); axis of symmetry: x = 2 vertex: (2, –3); axis of symmetry: x = 2 vertex: (–2, –3); axis of symmetry: x = –2 vertex: (–2, –3); axis of symmetry: x = –2 vertex: (2, 3); axis of symmetry: x = 2 vertex: (2, 3); axis of symmetry: x = 2 vertex: (–2, 3); axis of symmetry: x = –2
The correct response is:
vertex: (-2, -3); axis of symmetry: x = -2
The correct answer is: vertex: (-2, -3); axis of symmetry: x = -2.
To identify the vertex and axis of symmetry of the graph of the function y = 3(x + 2)2 - 3, we can use the standard form of a quadratic function, which is y = a(x - h)2 + k. In this case, a = 3, h = -2, and k = -3.
The vertex of a quadratic function in standard form is given by the coordinates (h, k). So, the vertex in this case is (-2, -3).
The axis of symmetry is a vertical line that passes through the vertex and divides the parabola into two equal halves. For a quadratic function in standard form, the equation of the axis of symmetry is x = h. Therefore, the axis of symmetry in this case is x = -2.
So, the correct response is vertex: (-2, -3); axis of symmetry: x = -2