Suppose 10 atoms of carbon (c) react with 20 atoms of oxygen(o) to form 10 molecules of carbon dioxide (co2) . According to the law of conservation of matter, how many atoms are present in this reaction
According to the law of conservation of matter, the total number of atoms before and after a reaction must be the same.
In this reaction:
10 atoms of carbon (C) react with 20 atoms of oxygen (O)
The reactants contain a total of 10 + 20 = 30 atoms.
After the reaction, 10 molecules of carbon dioxide (CO2) are formed. Each CO2 molecule contains 1 carbon atom and 2 oxygen atoms.
So, 10 molecules of CO2 contain a total of 10 x 1 = 10 carbon atoms and 10 x 2 = 20 oxygen atoms.
Therefore, the total number of atoms after the reaction is 10 (carbon atoms) + 20 (oxygen atoms) = 30 atoms, which is the same as the total number of atoms before the reaction.
Thus, according to the law of conservation of matter, there are 30 atoms present in this reaction.
According to the law of conservation of matter, the total number of atoms before and after a chemical reaction must remain the same.
To determine the number of atoms present in this reaction, we need to analyze the chemical formulas of the reactants and products.
In this reaction, 10 atoms of carbon (C) are reacting with 20 atoms of oxygen (O) to form 10 molecules of carbon dioxide (CO2).
In a carbon dioxide molecule (CO2), there is one atom of carbon and two atoms of oxygen.
So, in the reactants, we have a total of (10 * 1 = 10) atoms of carbon and (20 * 1 = 20) atoms of oxygen.
In the products, we have (10 * 1 = 10) atoms of carbon and (10 * 2 = 20) atoms of oxygen (2 atoms of oxygen per CO2 molecule, and there are 10 CO2 molecules).
Adding up the atoms in the reactants and products, we find that there are (10 + 20 = 30) atoms of carbon and (20 + 20 = 40) atoms of oxygen in total.
Therefore, the total number of atoms present in this reaction is 30 atoms of carbon and 40 atoms of oxygen.
To determine the number of atoms present in this reaction, we need to examine the chemical equation and count the number of atoms on both sides.
The given equation is:
10 C + 20 O2 → 10 CO2
Since carbon dioxide (CO2) is made up of one atom of carbon (C) and two atoms of oxygen (O), we know that for every molecule of CO2, there is one C atom and two O atoms.
Therefore, in the reaction, we have:
10 C atoms (from the 10 molecules of CO2)
+
2 * 10 O atoms (from the 10 molecules of CO2, accounting for the two oxygen atoms in each molecule)
Simplifying this, we get:
10 C atoms + 20 O atoms = 30 atoms
So, according to the law of conservation of matter, there are a total of 30 atoms present in this reaction.