An online data storage facility has 1.326 * 10^13 bytes of storage available. It has 2.6*10^4 customers. How many bytes of storage can each costumer use? Write your answer in scientific notion, expressed to the exact decimal place
To find out how many bytes of storage each customer can use, we need to divide the total storage available by the number of customers.
1.326 * 10^13 bytes / 2.6 * 10^4 customers
To divide numbers in scientific notation, we subtract the exponents:
1.326 / 2.6 = 0.5107692307
Then, we subtract the exponents of 10:
10^(13-4) = 10^9
Multiplying the result by 10^9:
0.5107692307 * 10^9
Therefore, each customer can use approximately 5.1 * 10^8 bytes of storage.
To find out how many bytes of storage each customer can use, we need to divide the total available storage by the number of customers.
Total bytes of storage available = 1.326 * 10^13
Number of customers = 2.6 * 10^4
Bytes of storage per customer = Total bytes of storage available / Number of customers
Bytes of storage per customer = (1.326 * 10^13) / (2.6 * 10^4)
To divide numbers in scientific notation, we can divide the coefficients and subtract the exponents:
Bytes of storage per customer = 1.326 / 2.6 * 10^(13-4)
Calculating the division: 1.326 / 2.6 = 0.510
Converting the result to scientific notation:
Bytes of storage per customer = 5.10 * 10^(-1+9)
Simplifying the exponent: -1 + 9 = 8
Final Answer: Each customer can use 5.10 * 10^8 bytes of storage.
To find out how many bytes of storage each customer can use, you need to divide the total storage capacity by the number of customers.
Step 1: Divide the total storage capacity by the number of customers:
1.326 * 10^13 bytes / 2.6 * 10^4 customers
To divide numbers in scientific notation, you subtract the exponents:
(1.326 / 2.6) * 10^(13-4) bytes
Step 2: Calculate the division of the coefficients (i.e. the decimal numbers) separately:
0.510 * 10^9 bytes
Step 3: Simplify the scientific notation:
5.10 * 10^8 bytes
Therefore, each customer can use approximately 5.10 * 10^8 bytes of storage.