A student holds a water balloon outside of an open window and let's go. The window is 10 meters above the ground, and the balloon is falling under the acceleration of gravity, which is 9.8 m/s2. If t=1 sec, what is the distance?
To find the distance traveled by the water balloon after 1 second, we can use the equation of motion:
distance = initial velocity * time + (1/2) * acceleration * time^2
Since the water balloon is being dropped from rest, the initial velocity is 0 m/s. We can substitute the given values into the equation:
distance = 0 * 1 + (1/2) * (9.8) * (1^2)
distance = 0 + (1/2) * (9.8) * 1
distance = 0 + 4.9
distance = 4.9 meters
Therefore, the distance traveled by the water balloon after 1 second is 4.9 meters.
To determine the distance traveled by the water balloon after t=1 second, we can use the equation of motion for free fall:
d = (1/2) * g * t^2
Where:
d = distance traveled
g = acceleration due to gravity
t = time
Plugging in the given values:
d = (1/2) * 9.8 m/s² * (1 s)^2
Simplifying the equation:
d = 4.9 m/s² * 1 s²
d = 4.9 m
Therefore, after 1 second, the water balloon will have fallen a distance of 4.9 meters.
To determine the distance the water balloon falls after 1 second, we can use the equation for the distance traveled by a falling object:
distance = 0.5 * acceleration * time^2
Given that the acceleration due to gravity (g) is 9.8 m/s^2 and the time (t) is 1 second, we can substitute these values into the equation:
distance = 0.5 * 9.8 * 1^2
distance = 0.5 * 9.8 * 1
distance = 4.9 meters
Therefore, the water balloon falls a distance of 4.9 meters after 1 second.