The height of an equilateral triangle equals the square root of 3 over 2 times the side length. Using 7/4 for the square root of 3, what is the approximate height in meters of an equilateral triangle with a side of 8 meters?
To find the height of an equilateral triangle, you can multiply the side length by the expression $\dfrac{\sqrt{3}}{2}$.
Given that $\sqrt{3} \approx \dfrac{7}{4}$ and the side length is 8 meters, we can substitute these values into the expression:
Height $= 8 \times \dfrac{7}{4} = \dfrac{56}{4} = 14$ meters.
Therefore, the approximate height of the equilateral triangle is 14 meters.
To find the height of an equilateral triangle, we can use the formula: height = √3/2 * side length
Given that the square root of 3 is approximately 7/4, we substitute this value into the formula:
height = (7/4) * 8
Calculating this expression:
height = (7 * 8) / 4
= 56 / 4
= 14 meters
Therefore, the approximate height of an equilateral triangle with a side length of 8 meters is 14 meters.
To find the approximate height of an equilateral triangle with a given side length, we can apply the formula you provided: height = (sqrt(3)/2) * side length.
Given: side length = 8 meters
Approximation: sqrt(3) = 7/4
First, let's substitute the values into the formula:
height = (7/4 * 8 * (sqrt(3)/2) = (7/4 * 8 * 7/4) meters
Now, let's simplify the expression:
height = (7 * 2 * 7) / (4 * 4) = (98/16) meters
Finally, let's simplify the fraction to its lowest terms:
height = 49/8 meters
Therefore, the approximate height of the equilateral triangle with a side length of 8 meters is 49/8 meters.