Hydrogen selenide (H_{2}*Se) reacts with water according to the following equation H 2 Se+H 2 O SeH^ - +H 3 O^ + In three to five sentences, identify the acid, base, conjugate acid, and conjugate base in this reaction. Use patterns in the periodic table to explain why the substances you identified acted as the acid and the base in this reaction
In this reaction, hydrogen selenide (H2Se) acts as the acid, while water (H2O) acts as the base. The conjugate acid is SeH- and the conjugate base is H3O+. Hydrogen selenide donates a proton (H+) to water, making it the acid, while water accepts the proton and forms the hydronium ion (H3O+), making it the base. The acidic properties of hydrogen selenide can be attributed to the fact that selenium (Se) is a nonmetal located in Group 16 of the periodic table, which tends to exhibit acidic properties when combined with hydrogen. Similarly, the basic properties of water can be attributed to the oxygen atom being a more electronegative element, which allows it to attract and accept protons.
In this reaction, hydrogen selenide (H2Se) is acting as the acid, while water (H2O) is acting as the base. The conjugate acid is SeH- (selenide ion), which is formed when H2Se donates a proton (H+). The conjugate base is H3O+ (hydronium ion), which is formed when H2O accepts a proton.
The identification of acid and base can be explained by patterns in the periodic table. In general, acid-base reactions involve the transfer of protons (H+ ions). Elements on the left side of the periodic table, such as hydrogen, tend to donate these protons and act as acids. Elements on the right side of the periodic table, like oxygen, tend to accept protons and act as bases. In this case, H2Se, being a compound of hydrogen, acts as the acid, while water, containing oxygen, acts as the base.
In the given reaction, hydrogen selenide (H2Se) acts as the acid, while water (H2O) acts as the base. The conjugate acid in the reaction is SeH-, produced when H2Se donates a proton (H+) to water. The conjugate base is H3O+, which is formed when water accepts the proton from H2Se.
To determine why H2Se acts as the acid and H2O as the base, we can look at the patterns in the periodic table. In this case, hydrogen selenide (H2Se) donates a proton (H+) to water, indicating its acidic nature. Selenide (Se-) is in Group 16/Chalcogens, just below oxygen (O) in Group 16. Since oxygen readily accepts protons to form H3O+ when dissolved in water, it acts as the base in this reaction. The trend in the periodic table suggests that elements in Group 16 tend to act as bases, while elements from Group 1 (such as hydrogen) tend to act as acids.