Mrs. Jennings wants to take her class on a field trip to the museum. The bus will cost a total of $100, and the museum will change $2 per student. The museum does not charge teachers for admission. What is the maximur of students that Mrs. Jennings can take to the museum without exceeding her budget of $150?

Question

Mrs. Jennings wants to take her class on a field trip to the museum. The bus will cost a total of $100, and the museum will change $2 per student. The museum does not charge teachers for admission. What is the maximur of students that Mrs. Jennings can take to the museum without exceeding her budget of $150?

Answer 1

Let's first consider the cost of the bus, which is $100. This leaves Mrs. Jennings with $150 - $100 = $<<150-100=50>>50 for the museum admission fees.

Since the museum charges $2 per student, Mrs. Jennings can take a maximum of $50 / $2 = <<50/2=25>>25 students to the museum. Answer: \boxed{25}.

Answer 2

To find out the maximum number of students Mrs. Jennings can take to the museum, we need to determine the cost per student and how many students can be accommodated within the budget.

First, we deduct the cost of the bus from the total budget:
$150 - $100 = $50

Next, we calculate the cost per student by dividing the remaining budget by the museum fee per student:
$50 ÷ $2 = 25

Therefore, Mrs. Jennings can take a maximum of 25 students to the museum without exceeding her budget of $150.

Answer 3

To find the maximum number of students Mrs. Jennings can take to the museum without exceeding her budget of $150, we need to set up and solve an inequality.

Let's denote the number of students as 's'.
The cost of the bus is a fixed amount of $100, regardless of the number of students.
The cost per student at the museum is $2, and since Mrs. Jennings is not charged for admission, the total cost for the students is $2*s.

So, the total cost of the field trip is $100 (for the bus) + $2*s (for the students).

We want this total cost to be less than or equal to Mrs. Jennings' budget of $150. Therefore, our inequality is:

100 + 2s ≤ 150

Now, let's solve this inequality to find the maximum number of students.

First, subtract 100 from both sides:
2s ≤ 150 - 100
2s ≤ 50

Then, divide both sides by 2 to isolate 's':
s ≤ 50/2
s ≤ 25

Therefore, the maximum number of students Mrs. Jennings can take to the museum without exceeding her budget of $150 is 25 students.