If the total mass of the product, mercuric oxide, HgO, is 433.2 grams, what is the total mass of Mercury and Oxygen on the reactants side of the equation?
To find the total mass of mercury and oxygen on the reactants side of the equation, we need to know the balanced chemical equation for the reaction. Without the equation, we cannot determine the specific reactants used or their stoichiometry.
To determine the total mass of mercury and oxygen on the reactants side of the equation, we need to know the balanced chemical equation for the reaction involving mercuric oxide, HgO.
If we assume the balanced chemical equation is:
2HgO -> 2Hg + O2
From the balanced equation, we can see that for every two moles of mercuric oxide (HgO), we obtain two moles of mercury (Hg) and one mole of oxygen gas (O2).
First, we need to determine the molar mass of mercuric oxide (HgO), which consists of one mercury atom and one oxygen atom. The molar mass of mercury (Hg) is 200.59 g/mol, and the molar mass of oxygen (O) is 16.00 g/mol.
Using these molar masses, we can calculate the molar mass of mercuric oxide:
Molar mass of HgO = (1 atom of Hg × 200.59 g/mol) + (1 atom of O × 16.00 g/mol)
= 200.59 g/mol + 16.00 g/mol
= 216.59 g/mol
Now, let's calculate the number of moles of mercuric oxide (HgO) in 433.2 grams of the compound. We can use the formula:
Number of moles = Mass / Molar mass
Number of moles of HgO = 433.2 g / 216.59 g/mol
≈ 2 moles
Since the balanced equation indicates that 2 moles of mercuric oxide gives 2 moles of mercury and 1 mole of oxygen gas, we can conclude that the total mass of mercury and oxygen on the reactants side is:
Total mass of mercury = 2 moles × 200.59 g/mol
= 401.18 grams
Total mass of oxygen = 1 mole × 16.00 g/mol
= 16.00 grams
Therefore, the total mass of mercury and oxygen on the reactants side is approximately 401.18 grams of mercury and 16.00 grams of oxygen.
To determine the total mass of mercury (Hg) and oxygen (O) on the reactants side of the equation for the formation of mercuric oxide (HgO), we need to know the balanced chemical equation for the reaction.
The balanced equation for the formation of mercuric oxide is:
2Hg + O2 → 2HgO
From the balanced equation, we can see that 2 moles of mercury (Hg) reacts with 1 mole of oxygen (O2) to produce 2 moles of mercuric oxide (HgO).
Now, let's find the molar masses of mercury (Hg) and oxygen (O):
- Molar mass of Hg = 200.59 grams/mol
- Molar mass of O = 16.00 grams/mol
To find the total mass of mercury and oxygen on the reactants side, we need to calculate the total number of moles of mercury and oxygen, and then multiply it by their respective molar masses:
Total mass of mercury = 2 moles of Hg × molar mass of Hg
Total mass of oxygen = 1 mole of O2 × (2 moles of O / 1 mole of O2) × molar mass of O
Calculating the total mass:
Total mass of mercury = 2 moles × 200.59 grams/mol = 401.18 grams
Total mass of oxygen = 1 mole × (2 moles / 1 mole) × 16.00 grams/mol = 32.00 grams
Therefore, the total mass of mercury and oxygen on the reactants side of the equation is 401.18 grams + 32.00 grams = 433.18 grams, which matches the given total mass of the product (mercuric oxide) in the question.