Is (−2, 6) a solution to the system of these linear equations: x+2y=10 and 3x+y=0 ? Why?(1 point) Responses Yes, because the graphs intersect at (−2, 6). Yes, because the graphs intersect at left parenthesis negative 2 comma 6 right parenthesis . No, because the graphs don’t intersect at (−2, 6). No, because the graphs don’t intersect at left parenthesis negative 2 comma 6 right parenthesis . No, because the graphs intersect at (−2, 6). No, because the graphs intersect at left parenthesis negative 2 comma 6 right parenthesis . Yes, because the graphs don’t intersect at (−2, 6).
No, because the graphs don’t intersect at (-2, 6).
here's all the answers.
Question 1.
10, -5
Question 2
Yes, because the graphs intersect at -2, 6
Question 3
-1,5
Question 4
Check the answer
Question 5
-1, 12
To determine if (-2, 6) is a solution to the system of equations, we need to check if substituting x = -2 and y = 6 into both equations results in true statements.
Let's start by calculating the left side of the equations:
For the first equation, x + 2y = 10:
(-2) + 2(6) = -2 + 12 = 10
For the second equation, 3x + y = 0:
3(-2) + 6 = -6 + 6 = 0
Now, let's compare the left sides of the equations with the right sides:
For the first equation, we have 10 = 10, which is true.
For the second equation, we have 0 = 0, which is also true.
Since both equations are true when substituting x = -2 and y = 6, we can conclude that (-2, 6) is indeed a solution to the system of equations.
Therefore, the correct response is: Yes, because the graphs intersect at (-2, 6).