Joseph wants to buy tickets for the baseball game and a team hat to wear to the game. He has $34.25. If the hat costs $12.50 and tickets cost $7.25 each, how many tickets can he buy
1 ticket
6 tickets
2 tickets
3 tickets
To determine how many tickets Joseph can buy, we need to subtract the cost of the hat from his total budget and then divide the remaining amount by the cost of each ticket.
Step 1: Subtract the cost of the hat from Joseph's budget:
$34.25 - $12.50 = $21.75
Step 2: Divide the remaining amount by the cost of each ticket:
$21.75 / $7.25 = 3
Therefore, Joseph can buy 3 tickets.
To determine how many tickets Joseph can buy, we need to consider the cost of the hat and the ticket price.
Let's calculate the total cost of the hat and tickets:
- The hat costs $12.50.
- The tickets cost $7.25 each.
So, the total cost of the tickets would be:
Total ticket cost = 7.25 * number of tickets
Since Joseph has $34.25 to spend, we can set up the following equation to find out how many tickets he can buy:
Total ticket cost + hat cost = $34.25
Substituting the values we have:
(7.25 * number of tickets) + 12.50 = 34.25
Now, let's solve the equation to find the number of tickets Joseph can buy:
7.25 * number of tickets = 34.25 - 12.5
7.25 * number of tickets = 21.75
Dividing both sides by 7.25:
number of tickets = 21.75 / 7.25
Therefore, Joseph can buy 3 tickets.
To determine the number of tickets Joseph can buy, we subtract the cost of the hat from his total money first: $34.25 - $12.50 = $<<34.25-12.50=21.75>>21.75.
Then, we divide the remaining money by the cost of each ticket to find the number of tickets he can buy: $21.75 / $7.25 = <<21.75/7.25=3>>3 tickets.
Therefore, Joseph can buy 3 tickets for the baseball game. Answer: \boxed{3 \text{ tickets}}.