A classroom of length (2b+1)cm has breadth b, what is the perimeter of the classroom
The perimeter of a rectangle is given by the formula: P = 2l + 2w, where l is the length and w is the width.
In this case, the length of the classroom is given as (2b+1) cm and the width is given as b cm.
Therefore, the perimeter of the classroom is:
P = 2(2b+1) + 2b
P = 4b + 2 + 2b
P = 6b + 2 cm
So, the perimeter of the classroom is 6b + 2 cm.
To find the perimeter of the classroom, we need to add up the lengths of all four sides.
The length of the classroom is given as (2b+1) cm.
The breadth of the classroom is given as b cm.
The perimeter is the sum of all four sides:
Perimeter = Length + Length + Breadth + Breadth
Let's calculate it step-by-step:
1. Length: (2b+1) cm
2. Length: (2b+1) cm
3. Breadth: b cm
4. Breadth: b cm
Now, let's add them up:
Perimeter = (2b+1) + (2b+1) + b + b
Simplifying the equation:
Perimeter = 2b + 2b + 1 + 1 + b + b
Combining similar terms:
Perimeter = 6b + 2
Therefore, the perimeter of the classroom is 6b + 2 cm.
To find the perimeter of the classroom, we need to add up the lengths of all four sides.
Given that the length of the classroom is (2b+1) cm and the breadth is b cm, we can visualize the classroom as a rectangle.
The perimeter of a rectangle can be calculated by adding twice the length and twice the breadth.
Perimeter = 2 * (Length + Breadth)
Substituting the given values,
Perimeter = 2 * [(2b + 1) + b]
Now, simplify the expression:
Perimeter = 2 * (3b + 1)
Finally, distribute the 2:
Perimeter = 6b + 2
Therefore, the perimeter of the classroom is 6b + 2 cm.