If 2 buses are needed to transport 75 students to the aquarium and 8 buses can transport 300 students to the aquarium, which proportion describes the relationship between the number of buses and the number of students? (Do not reduce the ratios to their lowest terms.
The proportion that describes the relationship between the number of buses and the number of students is:
{{{2/75 = 8/300}}}
To find the proportion that describes the relationship between the number of buses and the number of students, we can set up a ratio using the given information.
Let's represent the number of buses with "b" and the number of students with "s".
From the first sentence, we know that 2 buses are needed to transport 75 students, so we have the ratio:
2 buses / 75 students
Similarly, from the second sentence, we know that 8 buses can transport 300 students, so we have the ratio:
8 buses / 300 students
Therefore, the proportion that describes the relationship between the number of buses and the number of students is:
2/75 = 8/300
To find the proportion that describes the relationship between the number of buses and the number of students, we can set up a ratio.
Let's consider the first scenario: 2 buses are needed to transport 75 students.
The ratio of buses to students in this scenario is 2:75.
Now let's consider the second scenario: 8 buses can transport 300 students.
The ratio of buses to students in this scenario is 8:300.
To find the proportion that describes the relationship between the number of buses and the number of students, we can set up a proportion using the two ratios we found:
2/75 = 8/300
To solve this proportion, we can cross-multiply:
2 * 300 = 8 * 75
600 = 600
Since both sides of the equation are equal, we can conclude that the proportion is true:
2/75 = 8/300
Therefore, the proportion that describes the relationship between the number of buses and the number of students is 2:75 = 8:300.
Note: The ratio can be reduced to its simplest form, which would be 1:37.5 = 2:75. However, the question specifically asks not to reduce the ratios to their lowest terms.