Proportional Relationships Quick Check%0D%0A1 of 51 of 5 Items%0D%0A%0D%0AQuestion%0D%0AIf 2 buses are needed to transport 75 students to the aquarium and 8 buses can transport 300 students to the aquarium, which proportion describes the relationship between the number of buses and the number of students? (Do not reduce the ratios to their lowest terms.)(1 point)%0D%0AResponses%0D%0A%0D%0A275 ≠ 8300%0D%0AStart Fraction 2 over 75 End Fraction is not equal to Start Fraction 8 over 300 End Fraction%0D%0A%0D%0A275 = 3008%0D%0AStart Fraction 2 over 75 End Fraction equals Start Fraction 300 over 8 End Fraction%0D%0A%0D%0A752 = 8300%0D%0AStart Fraction 75 over 2 End Fraction equals Start Fraction 8 over 300 End Fraction%0D%0A%0D%0A275 = 8300
The correct answer is:
Start Fraction 2 over 75 End Fraction is not equal to Start Fraction 8 over 300 End Fraction
a b or c d
The correct answer is:
c d
Proportional Relationships Quick Check%0D%0A1 of 51 of 5 Items%0D%0A%0D%0AQuestion%0D%0AIf 2 buses are needed to transport 75 students to the aquarium and 8 buses can transport 300 students to the aquarium, which proportion describes the relationship between the number of buses and the number of students? (Do not reduce the ratios to their lowest terms.)(1 point)%0D%0AResponses%0D%0A%0D%0A275 ≠ 8300%0D%0AStart Fraction 2 over 75 End Fraction is not equal to Start Fraction 8 over 300 End Fraction%0D%0A%0D%0A275 = 3008%0D%0AStart Fraction 2 over 75 End Fraction equals Start Fraction 300 over 8 End Fraction%0D%0A%0D%0A752 = 8300%0D%0AStart Fraction 75 over 2 End Fraction equals Start Fraction 8 over 300 End Fraction%0D%0A%0D%0A275 = 8300
The correct answer is:
Start Fraction 2 over 75 End Fraction equals Start Fraction 8 over 300 End Fraction
The correct proportion that describes the relationship between the number of buses and the number of students is:
Start Fraction 2 over 75 End Fraction is not equal to Start Fraction 8 over 300 End Fraction
To solve this problem, we need to find the correct proportion that describes the relationship between the number of buses and the number of students.
The given information states that 2 buses are needed to transport 75 students, and 8 buses can transport 300 students.
We can write the first proportion as:
2/75 = x/300
To solve for x, we can cross-multiply:
2 * 300 = 75 * x
600 = 75x
Now, divide both sides of the equation by 75:
600/75 = x
x = 8
So, the correct proportion is:
2/75 = 8/300
Therefore, the correct response is:
Start Fraction 2 over 75 End Fraction equals Start Fraction 8 over 300 End Fraction