In changing a tire a hydraulic jack lifts 7468 N on its large piston which has an area of 28.27 cm^2 how much force must be excreted on the small piston if it has an area of 1.325 cm^2
To determine the force required on the small piston, we can use the principle of Pascal's law, which states that the pressure applied to a fluid is transmitted uniformly in all directions.
First, let's calculate the pressure applied on the large piston. We can use the formula:
Pressure = Force / Area
The area of the large piston is 28.27 cm^2, and the force lifted by the jack is 7468 N.
Pressure on the large piston = 7468 N / 28.27 cm^2
Now, according to Pascal's law, this pressure will be transmitted uniformly to the small piston as well.
Let's assume the force required on the small piston is F.
Using the same principle, we have:
Pressure on the small piston = F / 1.325 cm^2
Since the pressure is transmitted uniformly, the pressures on both pistons are equal.
Pressure on the large piston = Pressure on the small piston
7468 N / 28.27 cm^2 = F / 1.325 cm^2
To find F, we can rearrange the equation:
F = (7468 N / 28.27 cm^2) * 1.325 cm^2
F ≈ 350.67 N
Therefore, approximately 350.67 N of force must be exerted on the small piston.
To determine the force required on the small piston, we can use the principle of Pascal's law, which states that the pressure exerted in a fluid is transmitted equally in all directions.
First, we need to calculate the pressure exerted on the large piston using the formula:
Pressure = Force / Area
Given that the force exerted on the large piston is 7468 N and the area is 28.27 cm^2, we can substitute these values into the equation:
Pressure = 7468 N / 28.27 cm^2
Next, we can utilize Pascal's law to determine the force exerted on the small piston. According to Pascal's law, the pressure is the same throughout the fluid. Therefore, the pressure exerted on the small piston will be equal to the pressure exerted on the large piston.
Using the formula again:
Pressure = Force / Area
The pressure exerted on the small piston is equal to the pressure exerted on the large piston. The area of the small piston is 1.325 cm^2, so we can rearrange the formula to solve for force:
Force = Pressure * Area
Substituting the values we know:
Force = Pressure * 1.325 cm^2
Since the pressure from the previous calculation is the same on both pistons, the force required on the small piston is:
Force = (7468 N / 28.27 cm^2) * 1.325 cm^2
Simplifying:
Force ≈ 348.19 N
Therefore, approximately 348.19 N of force must be exerted on the small piston.
To determine the force exerted on the small piston, we can use the principle of Pascal's law, which states that the pressure in an enclosed fluid is transmitted equally in all directions. In this case, the hydraulic jack is filled with a fluid, and when force is applied to the large piston, the pressure is transmitted to the small piston.
First, we need to determine the pressure applied to the fluid by the large piston. We can use the formula:
Pressure = Force / Area
The force applied on the large piston is 7468 N, and the area is 28.27 cm^2. Converting the area to square meters:
Area = 28.27 cm^2 = 0.002827 m^2
Now, we can calculate the pressure:
Pressure = 7468 N / 0.002827 m^2
Next, we can use the pressure to find the force applied on the small piston:
Force = Pressure * Area
The area of the small piston is 1.325 cm^2, which is equal to 0.0001325 m^2. Plugging in the values:
Force = Pressure * 0.0001325 m^2
After obtaining the pressure from the previous calculation, you can substitute it into this equation to find the force exerted on the small piston.