A line has a slope of 2 and a y-intercept of 0. Which equation below correctly models the line?
The equation of a line in slope-intercept form is given by y = mx + b, where m is the slope and b is the y-intercept.
In this case, the slope is 2 and the y-intercept is 0. Plugging these values into the equation, we get:
y = 2x + 0
Simplifying, we get:
y = 2x
Therefore, the correct equation is y = 2x.
The equation of a line can be written in slope-intercept form:
y = mx + b,
where m is the slope of the line and b is the y-intercept.
Given that the line has a slope of 2 and a y-intercept of 0, we can substitute these values into the equation:
y = 2x + 0.
Since any number multiplied by 0 is 0, the equation simplifies to:
y = 2x.
Therefore, the equation that correctly models the line is y = 2x.
To find the equation of a line with a given slope and y-intercept, we can use the slope-intercept form of a linear equation, which is:
y = mx + b
Where:
- y is the dependent variable (usually representing the y-coordinate on a graph)
- x is the independent variable (usually representing the x-coordinate on a graph)
- m is the slope of the line
- b is the y-intercept, the point where the line crosses the y-axis
In this case, the slope (m) is given as 2, and the y-intercept (b) is given as 0. Therefore, the equation that correctly models the line is:
y = 2x + 0
However, since any number multiplied by 0 is still 0, we can simplify the equation further:
y = 2x
So, the final equation that correctly models the line with a slope of 2 and a y-intercept of 0 is y = 2x.