What is a counterexample for the conjecture? Conjecture: Any number that is divisible by 3 is also divisible by 6.
A counterexample for this conjecture would be the number 3 itself. 3 is divisible by 3 because the quotient is 1, but it is not divisible by 6 since the quotient is not a whole number.
To find a counterexample for the given conjecture, we need to find a number that is divisible by 3 but not divisible by 6.
A counterexample to this conjecture is the number 9.
9 is divisible by 3 because 9 ÷ 3 = 3, which gives a whole number quotient.
However, 9 is not divisible by 6 because 9 ÷ 6 = 1.5, which is not a whole number.
Therefore, the number 9 is a counterexample to the conjecture.
To find a counterexample for the conjecture, we need to find a number that is divisible by 3 but not divisible by 6.
To show that a number is divisible by another number, we use the concept of division. If a number is divisible by another number, it means that when we divide the first number by the second number, we get a whole number with no remainder.
Let's test the conjecture by trying to find a number that is divisible by 3 but not divisible by 6. We can start by choosing a number that is divisible by 3, such as 9.
When we divide 9 by 6, it gives us 1 with a remainder of 3. Since there is a remainder of 3, 9 is not divisible by 6.
Therefore, 9 is a counterexample for the conjecture that any number divisible by 3 is also divisible by 6.