We will toss a six-sided die. The sample space of outcomes from this dice toss is S = {1, 2, 3, 4, 5, 6}. Consider the following events:
A = the result is an even number = {2, 4, 6}
B = the result is at least four = {4, 5, 6}
Which outcomes are in the event (A∩B)?
The outcomes that are in the event (A∩B) are the outcomes that are in both A and B. Looking at the sets A = {2, 4, 6} and B = {4, 5, 6}, we can see that the only outcome that is in both sets is 6.
Therefore, the event (A∩B) = {6}.
Why would 4 not be included in the outcomes?
Apologies for the confusion. You are correct, the outcome 4 should be included in the event (A∩B) because it is in both event A (even number) and event B (at least four).
Therefore, the event (A∩B) = {4, 6}.
Which outcomes are in the event (A∪B)?
The outcomes that are in the event (A∪B) are the outcomes that are in either A or B, or both. Looking at the sets A = {2, 4, 6} and B = {4, 5, 6}, the outcomes in the union of A and B are:
A∪B = {2, 4, 5, 6}
Therefore, the outcomes in the event (A∪B) are 2, 4, 5, and 6.
To determine the outcomes in the intersection of events A and B, we need to find the numbers that are common to both sets.
Event A represents the set of even numbers: {2, 4, 6}.
Event B represents the numbers that are at least four: {4, 5, 6}.
The intersection of events A and B, denoted as A∩B, is the set of outcomes that are common to both sets. In this case, the outcomes that are in both events A and B are {4, 6}.
Therefore, the outcomes in the event (A∩B) are {4, 6}.
To find the outcomes that are in the event (A∩B), we need to determine the intersection of events A and B. The intersection of two events is the set of outcomes that are common to both events.
In this case, A = {2, 4, 6} and B = {4, 5, 6}. To find the intersection, we need to identify the outcomes that are present in both sets.
From the given sets, the common outcome is 6. Therefore, the event (A∩B) contains the outcome 6.
So, the outcomes in the event (A∩B) are {6}.