Find the slope of the line that passes through (4, -17) and (78, -47).
The slope of a line passing through two points $(x_1,y_1)$ and $(x_2, y_2)$ is given by the formula \[\text{slope} = \frac{y_2-y_1}{x_2-x_1}.\] Substituting $(4,-17)$ for $(x_1,y_1)$ and $(78,-47)$ for $(x_2,y_2)$, we find that the slope of the line is \[\frac{-47 - (-17)}{78- 4} = \frac{-47 + 17}{78 - 4} = \frac{-30}{74} = \boxed{-\frac{15}{37}}.\]
To find the slope of a line that passes through two points (x1, y1) and (x2, y2), we can use the formula:
slope = (y2 - y1) / (x2 - x1)
Given the points (4, -17) and (78, -47), we can substitute their coordinates into the formula:
slope = (-47 - (-17)) / (78 - 4)
= (-47 + 17) / 74
= -30 / 74
Now we can simplify the fraction:
slope = -15 / 37
Therefore, the slope of the line that passes through (4, -17) and (78, -47) is -15/37.
To find the slope of the line that passes through two points, we can use the slope formula:
Slope (m) = (y2 - y1) / (x2 - x1)
Let's calculate the slope using the given points:
x1 = 4
y1 = -17
x2 = 78
y2 = -47
Substituting these values into the slope formula, we get:
m = (-47 - (-17)) / (78 - 4)
Simplifying the calculation:
m = (-47 + 17) / (78 - 4)
= -30 / 74
The slope of the line passing through the points (4, -17) and (78, -47) is -30/74.