2co2+1h2o->1c2h2+3o2
is this balanced?
Yes, this chemical equation is balanced.
To determine if the equation is balanced, we need to count the number of atoms on each side of the equation.
On the left side, we have:
2 carbon (C) atoms
4 oxygen (O) atoms
2 hydrogen (H) atoms
On the right side, we have:
1 carbon (C) atom
4 oxygen (O) atoms
2 hydrogen (H) atoms
As you can see, the number of carbon and hydrogen atoms are not equal on both sides. This means that the equation is not balanced.
To balance the equation, we need to adjust the coefficients in front of each compound or element to make the number of atoms equal on both sides.
Here's the balanced equation:
2CO2 + 2H2O → C2H2 + 5O2
To check if the given chemical equation is balanced, we need to ensure that the number of each type of atom is the same on both sides of the equation.
Let's count the atoms on each side:
On the left side:
- 2 carbon atoms (C)
- 4 oxygen atoms (2 O2 molecules)
- 2 hydrogen atoms (H)
On the right side:
- 2 carbon atoms (C)
- 4 hydrogen atoms (2 H2 molecules)
- 8 oxygen atoms (3 O2 molecules)
As we can see, the number of carbon and hydrogen atoms are equal on both sides, but the number of oxygen atoms is not balanced.
To balance the equation, we need to calculate the least common multiple (LCM) of the coefficients in front of the molecules to adjust the number of oxygen atoms. In this case, the LCM of the coefficient of O2 on the left side (2) and the coefficient of O2 on the right side (3) is 6.
Now, let's multiply the coefficients by the appropriate numbers to balance the equation:
2CO2 + 2H2O -> 2C2H2 + 6O2
Now, let's count the atoms again:
On the left side:
- 4 carbon atoms (2 C2H2 molecules)
- 4 oxygen atoms (2 CO2 molecules)
- 4 hydrogen atoms (2 H2O molecules)
On the right side:
- 4 carbon atoms (2 C2H2 molecules)
- 12 oxygen atoms (6 O2 molecules)
- 4 hydrogen atoms (2 C2H2 molecules)
Now, the equation is balanced, as the number of each atom is the same on both sides.