The equation V=13πr2h
shows how the volume of a circular cone is related to its height and the radius of its base. When the cone is 3 feet high, the equation becomes V=πr2
. Find the volume of a 3-foot-high circular cone when the radius of its circular base is 2 feet. Round the answer to two decimal places.(1 point)
The volume of the circular cone is
cubic feet.
To find the volume of the cone, we can substitute the given values into the equation.
Given:
Height (h) = 3 feet
Radius (r) = 2 feet
Substituting these values into the equation V = 13πr^2h :
V = 13π(2^2)(3)
V = 13π(4)(3)
V = 13π(12)
V ≈ 150.796447
Rounding to two decimal places, the volume of the cone is approximately 150.80 cubic feet.
To find the volume of a 3-foot-high circular cone when the radius of its base is 2 feet, we can substitute the given values into the equation V = 13πr2h.
Given:
h = 3 feet
r = 2 feet
Substituting these values into the equation, we get:
V = 13π(2)2(3)
Simplifying the equation, we have:
V = 4π(3)
V = 12π
Now, we can round the answer to two decimal places:
V ≈ 12(3.14)
V ≈ 37.68
Therefore, the volume of the 3-foot-high circular cone with a radius of 2 feet is approximately 37.68 cubic feet.
To find the volume of a 3-foot-high circular cone with a radius of 2 feet, we can plug in the given values into the equation V = 13πr^2h.
Given:
h = 3 feet
r = 2 feet
Substituting these values into the equation, we have:
V = 13π(2)^2(3)
V = 13π(4)(3)
V = 13(12π)
V = 156π
Therefore, the volume of the 3-foot-high cone with a radius of 2 feet is 156π cubic feet. To round the answer to two decimal places, we can use the approximation π ≈ 3.14.
Volume ≈ 156 * 3.14 ≈ 489.84 cubic feet.