6CO2 + 6H2O → C6H12O6 + 4O2
How many molecules of carbon dioxide are involved in this reaction?
How many molecules of sugar are produced in this reaction?
How many atoms of carbon are on the left hand side of this equation? ______
How many atoms of carbon are on the right hand side of this equation? ______
Is the carbon balanced? _____
How many atoms of hydrogen are on the left hand side of this equation? ______
How many atoms of hydrogen are on the right hand side of this equation? ______
Is the hydrogen balanced? _____
How many atoms of oxygen are on the left hand side of this equation? ______
How many atoms of oxygen are on the right hand side of this equation? ______
Is the oxygen balanced? _____
Can you change one number above to balance the chemical equation?
There are 6 molecules of carbon dioxide involved in this reaction.
There is 1 molecule of sugar produced in this reaction.
There are 6 atoms of carbon on the left-hand side of the equation.
There are 6 atoms of carbon on the right-hand side of the equation.
The carbon is balanced.
There are 12 atoms of hydrogen on the left-hand side of the equation.
There are 12 atoms of hydrogen on the right-hand side of the equation.
The hydrogen is balanced.
There are 18 atoms of oxygen on the left-hand side of the equation.
There are 18 atoms of oxygen on the right-hand side of the equation.
The oxygen is balanced.
To balance the chemical equation, one could adjust the coefficient of oxygen on the left-hand side to be 5 instead of 6. This would result in the following balanced equation:
6CO2 + 6H2O → C6H12O6 + 5O2
To answer these questions, let's analyze the chemical equation:
6CO2 + 6H2O → C6H12O6 + 4O2
1. The coefficient in front of CO2 indicates that there are 6 molecules of carbon dioxide involved in this reaction.
2. The coefficient in front of C6H12O6 shows that 1 molecule of sugar is produced in this reaction.
3. On the left hand side, there are 6 carbon atoms in the 6 molecules of CO2.
4. On the right hand side, there are 6 carbon atoms in the molecule of C6H12O6.
The carbon is balanced because there are equal numbers of carbon atoms on both sides of the equation.
5. On the left hand side, there are 12 hydrogen atoms in the 6 molecules of H2O.
6. On the right hand side, there are 12 hydrogen atoms in the molecule of C6H12O6.
The hydrogen is balanced because there are equal numbers of hydrogen atoms on both sides of the equation.
7. On the left hand side, there are 12 oxygen atoms in the 6 molecules of CO2 and 6 oxygen atoms in the 6 molecules of H2O, summing up to a total of 18 oxygen atoms.
8. On the right hand side, there are 12 oxygen atoms in the 6 molecules of C6H12O6 and 8 oxygen atoms in the 4 molecules of O2, summing up to a total of 20 oxygen atoms.
The oxygen is unbalanced as there are more oxygen atoms on the right hand side of the equation.
To balance the equation, you can change the coefficient in front of H2O on the left hand side to 5, resulting in:
6CO2 + 5H2O → C6H12O6 + 4O2
Now, let's re-evaluate the oxygen balance:
On the left hand side, there are 6 carbon atoms, 10 hydrogen atoms, and 25 oxygen atoms.
On the right hand side, there are 6 carbon atoms, 12 hydrogen atoms, and 26 oxygen atoms.
The oxygen is still unbalanced, but in this case, there is no way to balance the equation without adding additional coefficients or changing the compounds involved in the reaction.
To determine the number of molecules or atoms involved in a chemical equation, we need to analyze each element separately.
1. How many molecules of carbon dioxide are involved in this reaction?
In the balanced equation, the coefficient in front of CO2 indicates the number of molecules. In this case, the coefficient for CO2 is 6, so there are 6 molecules of carbon dioxide involved.
2. How many molecules of sugar are produced in this reaction?
The balanced equation shows that 1 molecule of sugar (C6H12O6) is produced. As there is no coefficient in front of C6H12O6, we can assume a coefficient of 1.
3. How many atoms of carbon are on the left hand side of this equation?
The coefficient of carbon in CO2 is 1, and there are 6 molecules of CO2. Therefore, there are 6 carbon atoms on the left-hand side of the equation.
4. How many atoms of carbon are on the right hand side of this equation?
The coefficient of carbon in C6H12O6 is 6, and there is 1 molecule of C6H12O6. Hence, there are 6 carbon atoms on the right-hand side.
5. Is the carbon balanced?
Yes, the number of carbon atoms on both sides of the equation is equal, so carbon is balanced.
6. How many atoms of hydrogen are on the left hand side of this equation?
The coefficient of hydrogen in H2O is 2, and there are 6 molecules of H2O. Thus, there are 12 hydrogen atoms on the left-hand side.
7. How many atoms of hydrogen are on the right hand side of this equation?
The coefficient of hydrogen in C6H12O6 is 12, and there is 1 molecule of C6H12O6 present. Therefore, there are 12 hydrogen atoms on the right-hand side.
8. Is the hydrogen balanced?
Yes, the number of hydrogen atoms on both sides of the equation is equal, so hydrogen is balanced.
9. How many atoms of oxygen are on the left hand side of this equation?
The coefficient of oxygen in CO2 is 2, and there are 6 molecules of CO2. Hence, there are 12 oxygen atoms on the left-hand side.
The coefficient of oxygen in H2O is 1, and there are 6 molecules of H2O. Thus, there are 6 oxygen atoms on the left-hand side.
Overall, there are 12 + 6 = 18 oxygen atoms on the left-hand side.
10. How many atoms of oxygen are on the right hand side of this equation?
The coefficient of oxygen in C6H12O6 is 6, and there is 1 molecule of C6H12O6. Therefore, there are 6 oxygen atoms on the right-hand side.
11. Is the oxygen balanced?
No, the number of oxygen atoms on both sides of the equation is not equal. There are 18 oxygen atoms on the left-hand side and only 6 on the right-hand side, so oxygen is not balanced.
To balance the equation, we can adjust the coefficient in front of C6H12O6 to make the number of oxygen atoms equal on both sides. In this case, we need to multiply C6H12O6 by 3 to have a total of 18 oxygen atoms:
6CO2 + 6H2O → 3C6H12O6 + 4O2
Now the equation is balanced, and there are 18 oxygen atoms on both sides.