Solve the given system of linear equations by inspection. Enter 1 for one solution, 2 for no solution, or 3 for infinitely many solutions.%0D%0A%0D%0A2x−7y=4 %0D%0A%0D%0A2x−7y=−4 %0D%0A%0D%0A(1 point)
2
To solve the given system of linear equations by inspection, we need to compare the two equations and determine if they represent parallel lines, intersecting lines, or the same line.
Comparing the two equations:
2x - 7y = 4
2x - 7y = -4
We can observe that the left side of both equations is identical: 2x - 7y. However, the right side is different: 4 in the first equation and -4 in the second equation.
Since the left side of the equations are identical, but the right side is different, these equations represent parallel lines.
Therefore, the answer is 2 (no solution).
To solve the given system of linear equations by inspection, we need to examine the equations and see if we can determine the number of solutions.
The given system of equations is:
2x - 7y = 4
2x - 7y = -4
By inspection, we can see that both equations have the same coefficients for x and y. The only difference is the constant term on the right side of the equation.
If we subtract the second equation from the first equation, we get:
(2x - 7y) - (2x - 7y) = 4 - (-4)
0 = 8
This implies that 0 is equal to 8, which is not true. Therefore, there is no solution to the system of equations.
Hence, the answer is 2 (no solution).