stone with a mass of 10 kg sits on the ground. Gravity acts on the stone at a rate of 9.8 m/s2. What is the normal force acting on the stone, keeping it at rest?
The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, the stone is at rest, which means the normal force is equal in magnitude and opposite in direction to the gravitational force acting on the stone.
The gravitational force is given by the formula:
force = mass × acceleration
In this case, the mass of the stone is 10 kg, and the acceleration due to gravity is 9.8 m/s^2. Plugging these values into the formula, we get:
force = 10 kg × 9.8 m/s^2 = 98 N
So, the normal force exerted by the ground on the stone to keep it at rest is 98 Newtons.
To find the normal force acting on the stone, we need to understand that the normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, the stone is at rest on the ground, so the normal force is equal in magnitude and opposite in direction to the force of gravity.
The weight of the stone can be calculated using the formula:
Weight = mass × acceleration due to gravity
Given that the mass of the stone is 10 kg and the acceleration due to gravity is 9.8 m/s^2, we can substitute these values into the equation:
Weight = 10 kg × 9.8 m/s^2
Weight = 98 N
Since the stone is at rest, the normal force must be equal to the weight of the stone. Therefore, the normal force acting on the stone is 98 N.
To find the normal force acting on the stone, we need to understand the concept of Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.
In this case, the stone is at rest, which means its acceleration is zero. Therefore, the net force acting on the stone must also be zero. The normal force is one of the forces acting on the stone, so it must balance out the force of gravity.
The force of gravity can be calculated using the formula:
Force = mass x acceleration due to gravity
Given:
Mass of the stone (m) = 10 kg
Acceleration due to gravity (g) = 9.8 m/s^2
Substituting the values into the formula, we get:
Force of gravity = 10 kg x 9.8 m/s^2 = 98 N
Since the stone is at rest, the normal force must equal the force of gravity but act in the opposite direction:
Normal force = Force of gravity = 98 N
Therefore, the normal force acting on the stone, keeping it at rest, is 98 N.