Determine how much water must be added to 15.0mL of 10.0M NaOH to dilute the solution to 2.00M
To determine how much water must be added to the 15.0 mL of 10.0 M NaOH to dilute the solution to 2.00 M, we can use the formula for dilution:
C1V1 = C2V2
Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
In this case, we can rearrange the formula to find V2, the final volume of the diluted solution:
V2 = (C1V1) / C2
Plugging in the given values:
V2 = (10.0 M * 15.0 mL) / 2.00 M
V2 = 75 mL
Therefore, 75 mL of water must be added to the 15.0 mL of 10.0 M NaOH to dilute the solution to 2.00 M.
To determine how much water must be added to dilute the 15.0 mL of 10.0 M NaOH solution to a concentration of 2.00 M, we can use the formula for dilution:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution (10.0 M)
V1 = initial volume of the solution (15.0 mL)
C2 = final concentration of the solution (2.00 M)
V2 = final volume of the solution (unknown)
Rearranging the formula, we can solve for V2:
V2 = (C1 * V1) / C2
Substituting the given values into the equation:
V2 = (10.0 M * 15.0 mL) / 2.00 M
V2 = 150 mL
Therefore, you would need to add 150 mL of water to the 15.0 mL of 10.0 M NaOH to dilute the solution to 2.00 M.
To determine how much water must be added to a solution of NaOH to dilute it to a desired concentration, we can use the formula for dilution:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution (in this case, 10.0M NaOH)
V1 = initial volume of the solution (in this case, 15.0 mL)
C2 = final concentration of the solution (2.00M NaOH)
V2 = final volume of the solution (the volume we need to find, let's call it x mL)
Now, let's plug in the values we know into the formula:
(10.0M)(15.0 mL) = (2.00M)(x mL)
To solve for x, we can rearrange the equation:
(10.0M)(15.0 mL) / 2.00M = x mL
Now let's do the math:
x mL = (10.0M)(15.0 mL) / 2.00M
x mL = 150.0 mL
Therefore, you will need to add 150.0 mL of water to 15.0 mL of 10.0M NaOH to dilute the solution to 2.00M.