Write ionic equation for the reaction below.
Potassium chromate reacting with sulphuric acid
K2CrO4 + H2SO4 → K2SO4 + H2CrO4
Write ionic equation
2K+ + CrO42- + 2H+ + SO42- → 2K+ + SO42- + H2CrO4
To write the ionic equation for the reaction between potassium chromate (K2CrO4) and sulfuric acid (H2SO4), we need to first recognize that both compounds are ionic in nature.
The dissociation of potassium chromate (K2CrO4) in water can be represented as follows:
K2CrO4(s) → 2K+(aq) + CrO4^2-(aq)
Similarly, the dissociation of sulfuric acid (H2SO4) in water can be represented as:
H2SO4(l) → 2H+(aq) + SO4^2-(aq)
Now, let's write the balanced molecular equation for the reaction between potassium chromate and sulfuric acid:
K2CrO4(s) + H2SO4(l) → K2SO4(aq) + HCrO4(aq)
In this equation, potassium sulfate (K2SO4) and chromic acid (HCrO4) are formed as the products.
To obtain the ionic equation, we should separate all of the soluble ionic compounds into their individual ions:
K2CrO4(s) + H2SO4(l) → 2K+(aq) + CrO4^2-(aq) + K+(aq) + SO4^2-(aq) + H+(aq) + CrO4^2-(aq)
Now, we can cancel out any common ions on both sides of the equation. In this case, the CrO4^2- ions can be canceled out:
K2CrO4(s) + H2SO4(l) → 2K+(aq) + SO4^2-(aq) + H+(aq)
Therefore, the ionic equation for the reaction between potassium chromate and sulfuric acid is:
2K+(aq) + CrO4^2-(aq) + H+(aq) + SO4^2-(aq) → 2K+(aq) + SO4^2-(aq) + HCrO4(aq)
To write the ionic equation for the reaction between potassium chromate (K2CrO4) and sulfuric acid (H2SO4), we need to first understand the chemical formulas of the reactants and products.
The chemical formula of potassium chromate is K2CrO4, which dissociates completely in water to form potassium ions (K+) and chromate ions (CrO4^2-):
K2CrO4(s) → 2K+(aq) + CrO4^2-(aq)
The chemical formula of sulfuric acid is H2SO4. In aqueous solution, sulfuric acid dissociates into two hydrogen ions (H+) and a sulfate ion (SO4^2-):
H2SO4(aq) → 2H+(aq) + SO4^2-(aq)
To determine the ionic equation, we need to find out if any of the ions react with each other to form a precipitate, a gas, or a water molecule. Here, we have potassium ions (K+), chromate ions (CrO4^2-), hydrogen ions (H+), and sulfate ions (SO4^2-).
When potassium chromate reacts with sulfuric acid, the following reaction occurs:
2K+(aq) + CrO4^2-(aq) + 2H+(aq) + SO4^2-(aq) → 2K+(aq) + CrO4^2-(aq) + 2H2O(l) + SO4^2-(aq)
The potassium and sulfate ions are present on both sides of the reaction and therefore do not partake in any chemical reaction. The chromate and hydrogen ions react to form water (H2O):
CrO4^2-(aq) + 2H+(aq) → H2O(l)
Thus, the ionic equation for the reaction between potassium chromate and sulfuric acid is:
CrO4^2-(aq) + 2H+(aq) → H2O(l)