Let A = \{5, 7, 9\}; B =\ x|x; an even whole number less than 11), C = \{6, 8, 10, 12\} and D=\ x| xi! an odd whole number less than 12). Find AnB. Select the correct choice and fill in any answer boxes in your choice below.
A. A cap B=\ Box\ (Use a comma to separate answers as needed.) OB. The solution is the empty set.
A = {5, 7, 9}
B = {2, 4, 6, 8, 10}
C = {6, 8, 10, 12}
D = {1, 3, 5, 7, 9, 11}
To find A ∩ B (A cap B), we need to find the numbers that are common to both sets A and B.
In this case, the numbers that are common to both sets A and B are 6 and 8.
Therefore, A ∩ B = {6, 8}.
The correct choice is A.
To find A ∩ B (the intersection of A and B), we need to identify the elements that are common to both sets.
Set A = {5, 7, 9}
Set B = {x | x is an even whole number less than 11}
Since set B includes even whole numbers less than 11, we can see that the number 6 is present in both sets A and B. However, there are no other elements that satisfy the conditions in both A and B.
Therefore, A ∩ B = {6}, which means that the correct choice is A.
To find the intersection (AnB) between sets A and B, we need to identify all the elements that are common to both sets.
Set A is given as A = {5, 7, 9}, and set B is defined as the set of even whole numbers less than 11, which can be written as B = {2, 4, 6, 8, 10}.
Now, we need to find the elements that are present in both A and B. Upon comparing the two sets, we see that there are no common elements. Set A contains odd numbers, while set B consists of even numbers. Therefore, the intersection of A and B is the empty set, denoted by {}.
The correct choice is B. The solution is the empty set.