What is the minimum and maximum group size if the minimum charge to rent a bus is $200 and the maximum charge is $300, if
the cost is determined by the function f(a) = 5 + 50 ? (1 point)
The statement f (50 - 200 means that the group size of 50 reaches the minimum charge of $200, and f (30) = 300 means that
the group size of 30 reaches the maximum charge for the bus rental of $300.
• The statement f (50) = 300 means that the group size of 50 reaches the minimum charge of $300, and f(30) - 200 means that the group size of 30 reaches the maximum charge for the bus rental of $200.
• The statement f (30) = 300 means that the group size of 30 reaches the minimum charge of $300, and f (50) = 200 means that the group size of 50 reaches the maximum charge for the bus rental of $200.
The statement f (30) - 200 means that the group size of 30 reaches the minimum charge of $200, and f (50) = 300 means that
the group size of 50 reaches the maximum charge for the bus rental of $300.
The correct statement is: The statement f(50) = 300 means that the group size of 50 reaches the maximum charge for the bus rental of $300, and f(30) - 200 means that the group size of 30 reaches the minimum charge of $200.
The ice cream shop's profit for a day is modeled with the function f(= 500 + 30 where x is the number of days. How much did the shop make the first 6 days of operation? (1 point)
• $2300
O $3000
О $2700
О $3030
To find out how much the shop made in the first 6 days of operation, we need to substitute x = 6 into the function f(x) = 500 + 30x.
f(6) = 500 + 30(6) = 500 + 180 = $680.
Therefore, the shop made $680 in the first 6 days of operation.
The ice cream shop's profit for a day is modeled with the function f(= 500 + 30 where x is the number of days. How much did the shop make the first 6 days of operation? (1 point)
O $2300
O $3000
О $2700
О $3030
To find out how much the shop made in the first 6 days of operation, we need to substitute x = 6 into the function f(x) = 500 + 30x.
f(6) = 500 + 30(6) = 500 + 180 = $680.
Therefore, the shop made $680 in the first 6 days of operation.
Based on the given information, we can conclude that:
- f(50 - 200) = f(50) = 200, which means that a group size of 50 reaches the minimum charge of $200.
- f(30) = 300, which means that a group size of 30 reaches the maximum charge of $300.
- Therefore, the minimum group size to reach the minimum charge is 50, and the maximum group size to reach the maximum charge is 30.
To determine the minimum and maximum group size for the given pricing function f(a) = 5 + 50a, we need to understand how the function relates to the charges for renting a bus.
According to the information provided:
- The minimum charge to rent a bus is $200.
- The maximum charge to rent a bus is $300.
To find the minimum group size that reaches the minimum charge of $200, we solve the equation f(a) = 200. Substituting the function f(a) = 5 + 50a, we have:
5 + 50a = 200
Simplifying the equation, we get:
50a = 200 - 5
50a = 195
a = 195/50
a = 3.9
Therefore, the minimum group size that reaches the minimum charge of $200 is approximately 3.9.
To find the maximum group size that reaches the maximum charge of $300, we solve the equation f(a) = 300. Substituting the function f(a) = 5 + 50a, we have:
5 + 50a = 300
Simplifying the equation, we get:
50a = 300 - 5
50a = 295
a = 295/50
a = 5.9
Therefore, the maximum group size that reaches the maximum charge of $300 is approximately 5.9.
In conclusion:
- The minimum group size is approximately 3.9, and the minimum charge is $200.
- The maximum group size is approximately 5.9, and the maximum charge is $300.