Find intercepts of the graph of the equation.
1. y = -6
2. y = 3x+9
to find the x-intercepts, let y=0
to find the y-intercepts , let x=0
I think I got it right for number 2. My answer is "x=-3" and "y=9".
But I'm confused with number 1, 'cause there is no X.
:/
correct for the first one.
as to the second, you have a horizontal line running 6 units below the x-axis, so it can never cross the x-axis
whenever you have an equation in the form
y = k
it will be a horizontal line k units from the x-axis, so no x-intercept
if you have an equation in the form
x = c
it will be a vertical line c units from the y-axis, so no y-intercept.
To find the intercepts of the graph of an equation, we need to find the values of x or y when the other variable is equal to zero.
1. Equation: y = -6
To find the x-intercept, substitute y = 0 into the equation:
0 = -6
Since -6 is a constant, there is no x-variable involved. Thus, there is no x-intercept.
To find the y-intercept, substitute x = 0 into the equation:
y = -6
The y-intercept is the point (0, -6).
2. Equation: y = 3x + 9
To find the x-intercept, substitute y = 0 into the equation:
0 = 3x + 9
Solve for x:
3x = -9
x = -3
The x-intercept is the point (-3, 0).
To find the y-intercept, substitute x = 0 into the equation:
y = 3(0) + 9
y = 9
The y-intercept is the point (0, 9).