The sum of two numbers is 8,528. If one of the numbers is 800 more than the other, what is the smaller number?
Let's assume that the smaller number is x.
Since one of the numbers is 800 more than the other, we can write the equation:
x + (x + 800) = 8528
Simplifying the equation:
2x + 800 = 8528
Subtracting 800 from both sides:
2x = 7728
Dividing both sides by 2:
x = 3864
Therefore, the smaller number is 3864.
Let's call the smaller number x.
Since one of the numbers is 800 more than the other, we can express the other number as x + 800.
The sum of the two numbers is 8,528, so we can write the equation:
x + (x + 800) = 8,528.
Simplifying the equation, we have:
2x + 800 = 8,528.
Subtracting 800 from both sides of the equation, we get:
2x = 7,728.
Dividing both sides by 2, we have:
x = 3,864.
Therefore, the smaller number is 3,864.
To find the smaller number, we can set up a system of equations based on the given information.
Let's assume the smaller number is x, and the larger number is x + 800.
According to the problem, the sum of the two numbers is 8,528:
x + (x + 800) = 8,528
Now we can solve this equation to find the value of x.
Combining the like terms on the left-hand side:
2x + 800 = 8,528
Next, subtract 800 from both sides of the equation:
2x = 8,528 - 800
2x = 7,728
Finally, divide both sides of the equation by 2 to isolate x:
x = 7,728 / 2
x = 3,864
Therefore, the smaller number is 3,864.