Then they compared it with the number of visits made in an average week. Approximately 2×10^3
visits were reflected in their logbook during this two-week period, while only about 5×10^2
were reflected on an average week. How many times higher is the number of library visits before examination day compared to the library visits in an average week? Your answer should be a whole number.(1 point)
times
To find the number of times higher the number of library visits before the examination day is compared to the visits in an average week, we need to divide the number of visits before the examination day by the number of visits in an average week.
Number of visits before examination day = 2×10^3
Number of visits in an average week = 5×10^2
Times higher = (Number of visits before examination day) / (Number of visits in an average week)
= (2×10^3) / (5×10^2)
= (2/5) × (10^3/10^2)
= 0.4 × 10
= 4
Therefore, the number of library visits before examination day is 4 times higher than the number of visits in an average week.
It takes 10 years for a $100 monthly bank deposit to amount to $15,528.23 when invested at 5% interest compounded monthly. Round to the nearest place value, then express the amount $15,528.23 in the form of a×10^n where a is single digit.(1 point)
To find the amount in the form of a×10^n, we need to round the given amount, $15,528.23, to the nearest place value.
Rounded amount = $15,528
Since we are rounding the amount to the nearest place value, we can express it in the form of a×10^n as follows:
$15,528 = 1.5528 × 10^4
Therefore, the amount $15,528.23 can be expressed in the form of a×10^n as 1.5528 × 10^4.
It takes 10 years for a $100 monthly bank deposit to amount to $15,528.23 when invested at 5% interest compounded monthly. Round to the nearest place value, then express the amount $15,528.23 in the form of a×10^n where a is single digit.(1 point)
To express the amount $15,528.23 in the form of a×10^n where a is a single digit, we need to round the given amount to the nearest place value.
Rounded amount = $15,528
To express this rounded amount in the desired form, we can rewrite $15,528 as 1.5528 × 10^4. However, this is not in the form of a×10^n where a is a single digit.
To convert it to the desired form, we can divide both sides of the equation by 10^4:
⇒ (1.5528 × 10^4) / (10^4) = 1.5528
Therefore, the amount $15,528.23 can be expressed in the form of a×10^n as 1.5528 × 10^4, where a = 1 and n = 4.
To find the number of times higher the number of library visits before examination day compared to the visits in an average week, we need to calculate the ratio between the two.
The number of library visits before examination day is approximately 2×10^3 visits, while the number of visits in an average week is approximately 5×10^2 visits.
The ratio is calculated by dividing the number of visits before examination day by the number of visits in an average week:
Ratio = (2×10^3) / (5×10^2)
To simplify the calculation, we can cancel out one zero from both numbers:
Ratio = (2×10^2) / (5×10^1)
Next, we can divide 2 by 5:
Ratio = 2 / 5
This gives us the ratio of visits before examination day compared to visits in an average week. To find how many times higher it is, we need to calculate the reciprocal of this ratio:
Reciprocal ratio = 1 / (2 / 5)
To divide by a fraction, we multiply by the reciprocal:
Reciprocal ratio = 1 * (5 / 2)
Reciprocal ratio = 5 / 2
Finally, we can simplify the reciprocal ratio by dividing both numbers by their greatest common divisor (GCD), which is 1 in this case:
Reciprocal ratio = 5 / 2 = 2.5
Therefore, the number of library visits before examination day is approximately 2.5 times higher than the visits in an average week.
To find the number of times higher the number of library visits before examination day is compared to the visits in an average week, we need to calculate the ratio of these two numbers.
First, we calculate the ratio of the visits before examination day to the visits in an average week:
Number of visits before examination day = 2×10^3
Number of visits in an average week = 5×10^2
Ratio = Number of visits before examination day / Number of visits in an average week
Therefore, the ratio is:
Ratio = (2×10^3) / (5×10^2)
To simplify, we can cancel out the common factor of 10^2 from both numerator and denominator:
Ratio = (2×10^3) / (5×10^2) = (2/5) × (10^3/10^2) = (2/5) × (10^(3-2)) = (2/5) × 10 = 0.4 × 10 = 4
Hence, the number of library visits before examination day is 4 times higher compared to the visits in an average week.