In an examination 18 candidates pass math 17 pass physics 11 candidates passed both and 1 failed both find tge number that passed math only
To find the number of candidates who passed math only, we need to subtract the number of candidates who passed both math and physics (11) from the total number of candidates who passed math (18).
Therefore, the number of candidates who passed math only is 18 - 11 = <<18-11=7>>7.
To find the number of candidates that passed math only, we need to subtract the number of candidates who passed both math and physics from the total number of candidates who passed math.
Given:
Total number of candidates who passed math = 18
Total number of candidates who passed physics = 17
Number of candidates who passed both math and physics = 11
Number of candidates who passed math only = Total number of candidates who passed math - Number of candidates who passed both math and physics
Number of candidates who passed math only = 18 - 11 = 7
Therefore, 7 candidates passed math only.
To find the number of candidates who passed math only, we need to calculate the difference between the total number of candidates who passed math and the number of candidates who passed both math and physics.
Given the information provided, we know that:
- 18 candidates passed math,
- 17 candidates passed physics,
- 11 candidates passed both math and physics, and
- 1 candidate failed both subjects.
To calculate the number of candidates who passed math only, we can subtract the number of candidates who passed both subjects from the total number of candidates who passed math.
Math only = Total Passed Math - Passed Both Math and Physics
Math only = 18 - 11
Math only = 7
Therefore, 7 candidates passed math only.