A submarine is diving at a depth of 500 meters. Every 3 minutes, it descends another 50 meters. It then reaches a depth of 1,000 meters.
What is the distance that the submarine descended?
*
1 point
1,000 meters
750 meters
500 meters
250 meters
The submarine descends 50 meters every 3 minutes. To reach a depth of 1,000 meters, the submarine needs to descend 500 meters more than its initial depth.
Since the submarine starts at a depth of 500 meters, it descends 50 meters every 3 minutes for 500 meters, which is a total of 10 intervals of 3 minutes.
Therefore, the submarine descends a total distance of 10 * 50 = 500 meters.
So, the submarine descends 500 meters.
To find the total distance that the submarine descended, we can calculate the sum of the distances it descends every 3 minutes.
First, let's find the number of times the submarine descends by dividing the total depth by the descent distance every 3 minutes:
500 meters / 50 meters = 10 times
The submarine descends 10 times, so we can multiply the number of times it descends by the descent distance:
10 times * 50 meters = 500 meters
Therefore, the distance that the submarine descended is 500 meters. This corresponds to option C.
To determine the distance that the submarine descended, we need to calculate the total sum of its descents.
Given that the submarine descends 50 meters every 3 minutes, we can calculate the number of times it descends by dividing the total depth (1,000 meters) by the descent rate (50 meters):
Number of descents = Total depth / Descent rate
Number of descents = 1,000 meters / 50 meters = 20 descents
Now that we know the number of descents, we can find the total distance descended by multiplying the descent rate (50 meters) by the number of descents:
Total distance descended = Descent rate * Number of descents
Total distance descended = 50 meters * 20 descents = 1,000 meters
Therefore, the distance that the submarine descended is 1,000 meters.