A roller coaster begins at the top of a hill. If it accelerates at the rate of 2 m/s and has a mass of 2000 kg. What net force is acting on it
To calculate the net force acting on the roller coaster, we can use Newton's second law of motion:
\[F = ma\]
where F is the net force, m is the mass, and a is the acceleration.
Given:
Mass (m) = 2000 kg
Acceleration (a) = 2 m/s²
Substituting the given values into Newton's second law of motion, we get:
\[F = (2000 \, \text{kg})(2 \, \text{m/s²})\]
\[F = 4000 \, \text{kg·m/s²}\]
Therefore, the net force acting on the roller coaster is 4000 kg·m/s².
To calculate the net force acting on the roller coaster, you need to use Newton's second law of motion, which states that the net force (F_net) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a).
Given:
Mass (m) = 2000 kg
Acceleration (a) = 2 m/s²
Using the formula F_net = m * a, we can substitute the given values:
F_net = 2000 kg * 2 m/s²
= 4000 kg * m/s²
= 4000 N
Therefore, the net force acting on the roller coaster is 4000 Newtons (N).
To find the net force acting on the roller coaster, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.
Given:
Mass of the roller coaster (m) = 2000 kg
Acceleration (a) = 2 m/s²
Using the formula: F = m * a
Substituting the given values:
F = 2000 kg * 2 m/s²
F = 4000 kg⋅m/s²
Therefore, the net force acting on the roller coaster is 4000 Newtons (N).