Georgia Connections Academy is selling tickets to its Spring Fling. Adult tickets cost $4 and student tickets cost $2.50. The school makes $2,820. Write an equation that represents this situation to find the cost of all adult and student tickets sold. Use the variable s for student tickets and a for adult tickets sold. (7 points) Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse. Write an equation that represents this situation to find the cost of all adult and student tickets sold. Use the variable s for student tickets and a for adult tickets sold. Response area a + Response area s = Response area 900 tickets are sold for the spring fling. Write an equation to represent this situation. a + Response area = Response area Use the above system of equations to determine how many adult and student tickets were sold. Response area adult tickets and Response area student tickets were sold.

The equation that represents the situation to find the cost of all adult and student tickets sold is:

4a + 2.50s = 2820

The equation that represents the situation for 900 tickets sold is:
a + s = 900

Using the above system of equations, we can determine that adult tickets sold would be 400 and student tickets sold would be 500.

the last one is incorrect

I apologize for the mistake. Thank you for pointing it out. Let's correct it:

The equation that represents the situation for 900 tickets sold is:

a + s = 900

Using the above system of equations, we can determine that adult tickets sold would be 900 - s, and student tickets sold would be s.

how did you find that answer

My apologies for the confusion caused. To find the solution, we can use the given information and the system of equations provided.

The equation representing the cost of all adult and student tickets sold is:

4a + 2.50s = 2820

The equation representing the total number of tickets sold is:

a + s = 900

To determine the number of adult and student tickets sold, we can solve this system of equations simultaneously. Here's how we can do it:

1. Solve the second equation for a:

a = 900 - s

2. Substitute this expression for a into the first equation:

4(900 - s) + 2.50s = 2820

3. Simplify and solve for s:

3600 - 4s + 2.50s = 2820

-1.50s = 2820 - 3600

-1.50s = -780

s = -780 / -1.50

s = 520

4. Substitute the value of s back into the second equation to find a:

a + 520 = 900

a = 900 - 520

a = 380

Therefore, the number of adult tickets sold is 380 and the number of student tickets sold is 520.

To write an equation representing the cost of all adult and student tickets sold, we need to consider the cost of each type of ticket and the total amount made.

Let's use the variable "a" for the number of adult tickets sold and "s" for the number of student tickets sold.

Since adult tickets cost $4 each and student tickets cost $2.50 each, the equation is:
4a + 2.50s = 2820

To represent the situation where 900 tickets were sold, we can use the equation:
a + s = 900

Now, let's solve this system of equations to find the values of "a" and "s".

To find the cost of all adult and student tickets sold, we need to set up an equation based on the given information.

Let's start by assigning variables to the unknown quantities:

a = number of adult tickets sold
s = number of student tickets sold

We know that adult tickets cost $4 and student tickets cost $2.50.

The total amount made from selling tickets is $2,820.

Now we can set up the equation:

4a + 2.50s = 2820

This equation represents the total cost of all adult and student tickets sold.

Next, let's move on to the second part of the problem.

We are told that a total of 900 tickets were sold for the Spring Fling.

So we can set up another equation based on this information:

a + s = 900

This equation represents the total number of tickets sold.

Now we have a system of equations:

4a + 2.50s = 2820
a + s = 900

Finally, we can use this system of equations to determine how many adult and student tickets were sold.

To find the solution, you can use methods such as substitution, elimination, or graphing.