What mass of rhodium contains as many
atoms as there are zirconium atoms in 24 g of
zirconium?
Answer in units of g.
To find the mass of rhodium that contains the same number of atoms as 24 g of zirconium, we need to compare their molar masses.
First, we need to determine the number of zirconium atoms in 24 g of zirconium. We can use Avogadro's number, which states that 1 mole of any substance contains 6.022 × 10^23 atoms.
The molar mass of zirconium (Zr) is 91.22 g/mol. This means that 1 mole of zirconium weighs 91.22 grams.
To calculate the number of moles of zirconium in 24 g, we divide the mass by the molar mass:
24 g Zr / 91.22 g/mol = 0.263 moles Zr
Now, we need to find the molar mass of rhodium (Rh). The molar mass of rhodium is 102.91 g/mol.
To find the mass of rhodium equivalent to 0.263 moles, we multiply the number of moles by the molar mass:
0.263 moles Rh * 102.91 g/mol = 27.04 g Rh
Therefore, the mass of rhodium that contains the same number of atoms as there are zirconium atoms in 24 g of zirconium is 27.04 g.
How many formula units are in 5.5 g of
alumina (Al2O3)?
Answer in units of formula units.
To determine the number of formula units in 5.5 g of alumina (Al2O3), we need to use the molar mass of the compound.
The molar mass of Al2O3 can be calculated by summing the atomic masses of aluminum (Al) and oxygen (O):
Atomic mass Al = 26.98 g/mol
Atomic mass O = 16.00 g/mol
Molar mass Al2O3 = [(2 x 26.98) + (3 x 16.00)] g/mol
Molar mass Al2O3 = 101.96 g/mol
Now, we can use the molar mass to convert grams of Al2O3 to moles:
5.5 g Al2O3 / 101.96 g/mol = 0.0539 moles Al2O3
According to Avogadro's number, 1 mole of any substance contains 6.022 × 10^23 formula units.
To find the number of formula units in 0.0539 moles, we multiply by Avogadro's number:
0.0539 moles Al2O3 x (6.022 × 10^23 formula units/mole) = 3.24 × 10^22 formula units
Therefore, there are approximately 3.24 × 10^22 formula units in 5.5 g of alumina (Al2O3).
To determine the mass of rhodium that contains the same number of atoms as there are zirconium atoms in 24 g of zirconium, we need to use Avogadro's number and the molar masses of the elements.
1. Find the number of Zirconium atoms in 24 g of Zirconium:
- The molar mass of Zirconium (Zr) is 91.22 g/mol.
- Calculate the number of moles in 24 g of Zirconium:
number of moles = mass / molar mass
number of moles = 24 g / 91.22 g/mol
- Use Avogadro's number (6.022 x 10^23) to convert moles to atoms:
number of atoms = number of moles * Avogadro's number
2. Determine the mass of Rhodium containing the same number of atoms:
- Find the molar mass of Rhodium (Rh), which is 102.9 g/mol.
- Use Avogadro's number to convert the number of atoms to moles:
number of moles = number of atoms / Avogadro's number
- Calculate the mass of Rhodium:
mass of Rhodium = number of moles * molar mass
Let's plug in the values and calculate it:
Number of moles of Zirconium:
number of moles = 24 g / 91.22 g/mol
number of moles = 0.2631 mol
Number of Zirconium atoms:
number of atoms = 0.2631 mol * 6.022 x 10^23
number of atoms = 1.583 x 10^23 atoms
Number of moles of Rhodium:
number of moles = 1.583 x 10^23 atoms / 6.022 x 10^23
number of moles = 0.2631 mol
Mass of Rhodium:
mass of Rhodium = 0.2631 mol * 102.9 g/mol
mass of Rhodium = 27.04 g
Therefore, the mass of rhodium that contains the same number of atoms as there are zirconium atoms in 24 g of zirconium is approximately 27.04 g.
To find the mass of rhodium that contains the same number of atoms as there are in 24 g of zirconium, we need to use the concept of molar mass and Avogadro's number.
First, determine the number of zirconium atoms in 24 g of zirconium. To do this, we'll use the molar mass of zirconium (Zr), which is 91.22 g/mol.
Number of moles of zirconium = mass / molar mass
Number of moles of zirconium = 24 g / 91.22 g/mol
Next, we'll use Avogadro's number, which is 6.022 x 10^23 atoms/mol, to find the number of zirconium atoms.
Number of zirconium atoms = number of moles of zirconium * Avogadro's number
Number of zirconium atoms = (24 g / 91.22 g/mol) * (6.022 x 10^23 atoms/mol)
Now that we know the number of zirconium atoms, we can find the mass of rhodium that contains the same number of atoms.
To do this, we'll use the molar mass of rhodium (Rh), which is 102.91 g/mol.
Mass of rhodium = number of zirconium atoms * molar mass of rhodium / Avogadro's number
Mass of rhodium = [(24 g / 91.22 g/mol) * (6.022 x 10^23 atoms/mol)] * (102.91 g/mol) / (6.022 x 10^23 atoms/mol)
Simplifying the equation, we get:
Mass of rhodium = (24 g * 102.91 g) / 91.22 g
Calculating this expression will give us the mass of rhodium in grams that contains the same number of atoms as there are zirconium atoms in 24 g of zirconium.