def sum(n)

if n<1:
return 0
else: return n+sum(n-1)
result = sum(n-1)
result=sum(100)
print(result)
how could the code be altered to print the sum of the first 10 numbers in the sequence 3n-1

You can alter the code to print the sum of the first 10 numbers in the sequence 3n - 1 by modifying the `sum()` function and calling it with the appropriate argument.

Here is the modified code:

```python
def sum(n):
if n < 1:
return 0
else:
return 3*n - 1 + sum(n-1)

result = sum(10)
print(result)
```

In this code, the `sum(n)` function calculates the sum of the first `n` numbers in the sequence 3n - 1. By calling `sum(10)`, we are calculating the sum of the first 10 numbers in the sequence. The result is then printed to the console.

To alter the code to print the sum of the first 10 numbers in the sequence 3n-1, you can make the following changes:

```python
def sum_of_sequence(n):
if n < 1:
return 0
else:
return (3*n - 1) + sum_of_sequence(n-1)

result = sum_of_sequence(10)
print(result)
```

In this modified code, we have renamed the function to `sum_of_sequence` to reflect its purpose of calculating the sum of the sequence 3n-1. Additionally, we have replaced `n` with `(3*n - 1)` in the return statement of the recursive function to reflect the sequence's formula. Finally, we pass the argument `10` to the `sum_of_sequence` function to calculate the sum of the first 10 numbers in the sequence, and then print the result.

To alter the code to print the sum of the first 10 numbers in the sequence 3n-1, you need to make the following changes:

1. Modify the `sum` function to compute the sum of the sequence 3n-1 instead of a summation of consecutive numbers.

Here's the modified code:

```python
def sum_sequence(n):
if n == 0:
return 0
else:
return (3 * n - 1) + sum_sequence(n - 1)

result = sum_sequence(10)
print(result)
```

In the modified code:

- The function `sum_sequence` is defined, which takes an input `n`, representing the index of the term in the sequence, and returns the sum of the sequence up to that index.
- Inside the function, if `n` is 0 (indicating the first term), the function simply returns 0.
- Otherwise, it recursively computes the sum by adding the term `3 * n - 1` to the sum of the sequence up to the previous index `n - 1`.
- Finally, the code calls `sum_sequence(10)` to get the sum of the first 10 numbers in the sequence and prints the result.

With these modifications, the code will correctly calculate and print the sum of the first 10 numbers in the sequence 3n-1.