What is the slope of the line that passes through the pair of points?
(-5/3,-1), (-2,9/2)
The formula for finding the slope of a line passing through two points (x1, y1) and (x2, y2) is given by the formula:
m = (y2 - y1) / (x2 - x1)
Plugging in the coordinates given in the problem, we have:
m = ((9/2) - (-1)) / (-2 - (-5/3))
= (9/2 + 1) / (-2 + 5/3)
= (9/2 + 2/2) / (-2 + 15/3)
= (11/2) / (-2 + 15/3)
= (11/2) / (6/3 + 15/3)
= (11/2) / (21/3)
= (11/2) / (7)
= 11/14
Therefore, the slope of the line passing through the points (-5/3, -1) and (-2, 9/2) is 11/14.
To find the slope of the line that passes through the pair of points (-5/3, -1) and (-2, 9/2), we can use the formula for calculating slope:
slope = (y2 - y1) / (x2 - x1)
Let's substitute the given values into the formula:
x1 = -5/3, y1 = -1
x2 = -2, y2 = 9/2
So, the slope is:
slope = (9/2 - (-1)) / (-2 - (-5/3))
= (9/2 + 2/3) / (-2 + 5/3)
To simplify the expression, we need a common denominator:
slope = (27/6 + 4/6) / (-6/3 + 5/3)
= 31/6 / (-1/3)
= (31/6) * (-3/1)
= -31/2
Therefore, the slope of the line is -31/2.
To find the slope of a line passing through two points, we can use the formula:
m = (y2 - y1) / (x2 - x1)
Let's label the points:
Point 1: (-5/3, -1)
Point 2: (-2, 9/2)
Now we can substitute the values into the formula:
m = (9/2 - (-1)) / (-2 - (-5/3))
First, let's simplify the numerator:
m = (9/2 + 1) / (-2 + 5/3)
m = (9/2 + 1) / (-2 + 15/3)
m = (9/2 + 1) / (-2 + 5)
m = (9/2 + 1) / 3
m = (9/2 + 2/2) / 3
m = 11/2 / 3
Now, let's divide the numerator by the denominator:
m = (11/2) * (1/3)
m = 11/6
Therefore, the slope of the line passing through the given points is 11/6.