Use the polynomial identity x^2-a^2=(x+a)(x-a) to rewrite x^2-196 Which polynomial does this establish?
x^2-196=(x-14)(x-14)
x^2-196=(x+14)(x-14)
x^2-196=(x+98)(x-98)
x^2-196=(x-98)(x-98)
The correct answer is:
x^2-196=(x+14)(x-14)
The correct polynomial that can be established using the polynomial identity x^2-a^2=(x+a)(x-a) to rewrite x^2-196 is:
x^2-196=(x+14)(x-14)
To determine which polynomial the given expression, x^2 - 196, is equal to using the polynomial identity x^2 - a^2 = (x + a)(x - a), we need to find the value of 'a' that gives us the perfect square. In this case, 'a' is equal to 14.
Using the polynomial identity x^2 - a^2 = (x + a)(x - a), we can rewrite x^2 - 196 as:
x^2 - 196 = (x + 14)(x - 14).
Therefore, the correct polynomial that x^2 - 196 is equivalent to is (x + 14)(x - 14).